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zubka84 [21]
3 years ago
6

Write 3 1/8 as an improper fraction. 15/ 18/8 21/8 25/8

Mathematics
1 answer:
ser-zykov [4K]3 years ago
7 0

Answer:

25/8 :))

Step-by-step explanation:

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Common difference r will be the difference between next two values of number row, so we take e.g. second minus first: r=9.4-6=3.4. You can see, that this value is constant as we go through next pairs of values.
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Divide forty-seven point five by ten
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Divide forty-seven point five by ten

Write:-

47.5 ÷ 10 = 4.75

<span>Divide forty-seven point five by ten = 4.75</span>
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Hypothesis Testing
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Answer:

<u>Problem 1</u>: We conclude that less than or equal to 50% of adult Americans without a high school diploma are worried about having enough saved for retirement.

<u>Problem 2</u>: We conclude that the volume of Google stock has changed.

Step-by-step explanation:

<u>Problem 1:</u>

We are given that in a recent survey conducted by Pew Research, it was found that 156 of 295 adult Americans without a high school diploma were worried about having enough saved for retirement.

Let p = <em>proportion of adult Americans without a high school diploma who are worried about having enough saved for retirement</em>

So, Null Hypothesis, H_0 : p \leq 50%    {means that less than or equal to 50% of adult Americans without a high school diploma are worried about having enough saved for retirement}

Alternate Hypothesis, H_A : p > 50%     {means that a majority of adult Americans without a high school diploma are worried about having enough saved for retirement}

This is a right-tailed test.

The test statistics that would be used here is <u>One-sample z-test</u> for proportions;

                       T.S.  =  \frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion of adult Americans who were worried about having enough saved for retirement = \frac{156}{295} = 0.53

           n = sample of adult Americans = 295

So, <u><em>the test statistics</em></u> =  \frac{0.53-0.50}{\sqrt{\frac{0.50(1-0.50)}{295} } }

                                    =  1.03

The value of z-test statistics is 1.03.

<u>Also, the P-value of the test statistics is given by;</u>

              P-value = P(Z > 1.03) = 1 - P(Z \leq 1.03)

                           = 1 - 0.8485 = <u>0.1515</u>

Now, at a 0.05 level of significance, the z table gives a critical value of 1.645 for the right-tailed test.

Since the value of our test statistics is less than the critical value of z as 1.03 < 1.645, <u><em>so we insufficient evidence to reject our null hypothesis</em></u> as it will not fall in the rejection region.

Therefore, we conclude that less than or equal to 50% of adult Americans without a high school diploma are worried about having enough saved for retirement.

<u>Problem 2:</u>

We are given that a random sample of 35 trading days in 2014 resulted in a  sample mean of 3.28 million shares with a standard deviation of 1.68 million shares.

Let \mu = <em>mean daily volume in Google stock</em>

So, Null Hypothesis, H_0 : \mu = 5.44 million shares    {means that the volume of Google stock has not changed}

Alternate Hypothesis, H_A : \mu \neq 5.44 million shares     {means that the volume of Google stock has changed}

This is a two-tailed test.

The test statistics that would be used here is <u>One-sample t-test statistics</u> because we don't know about the population standard deviation;

                       T.S.  =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean volume in Google stock = 3.28 million shares

            s = sample standard deviation = 1.68 million shares

           n = sample of trading days = 35

So, <u><em>the test statistics</em></u> =  \frac{3.28-5.44}{\frac{1.68}{\sqrt{35} } }  ~ t_3_4

                                    =  -7.606

The value of t-test statistics is -7.606.

<u>Also, the P-value of the test statistics is given by;</u>

              P-value = P(t_3_4 < -7.606) = Less than 0.05%

Now, at a 0.05 level of significance, the t table gives a critical value of -2.032 and 2.032 at 34 degrees of freedom for the two-tailed test.

Since the value of our test statistics doesn't lie within the range of critical values of t, <u><em>so we sufficient evidence to reject our null hypothesis</em></u> as it will fall in the rejection region.

Therefore, we conclude that the volume of Google stock has changed.

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F(x) = x3 – 3x2 - x + 3<br> what is the domain and range?
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Answer:

Domain: (-∞,∞)

Range: (-∞,∞)

Hope this helps.

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The area of an 13-cm-wide rectangle is 234 cm2. What is its length?<br> The length is?
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watch a tutorial on how to find the length of a rectangle

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