Total cost for tiles and paints is $924.
Step-by-step explanation:
We have been given that a community hall is in the shape of a cuboid. The hall is 40m long 15m high and 3m wide.
The paint will be required for 4 walls and ceiling.
Let us find area of walls and ceiling.
Therefore, the area of walls and ceiling is 1410 square meters.
Given: Cost for 10 litre of paint is $10 and 10 litre paint covers 25 square meter. Therefore,
Therefore, the total painting cost is $564.
Tiles will be required for floor. Let us find the area of floor.
Given: 1m squared floor tiles costs $3. So,
Therefore, the total cost for tiles is $360.
Now let us find combined total cost of tiles and paint.
Therefore, the combined total cost of tiles and paint is $924.
Check the picture below.
now, an angle bisector I assume, since it intersects the opposite segment at D and then at E. An angle bisector cuts an angle in two equal halves, so if ∡CAB is 82°, that just means that ∡CAE is one of those halves, or 41°.
Answer:
Below in bold.
Step-by-step explanation:
Because the 2 sides marked with the double lines are equal:
5y-1 = 2y+11
3y = 12
y = 4.
Also :
3x-5 + 2(2x+5) = 180
3x - 5 + 4x + 10 = 180
7x = 180 + 5 -10
7x = 175
x = 175/7 = 25.
We have that
<span>y = -x</span>²<span>+8x
we know that
when the ball hint the ground is the x-intercepts of the graph
the x-intercepts is for y=0
so
0=-x</span>²+8x--------> x²-8x=0----> x*(x-8)=0
the solution is
x=0
x=8
the x intercepts are the points (0,0) and (8,0)
the distance between the x intercepts points =[8-0]-----> 8 ft
the answer is
8 ft
see the attached figure