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liq [111]
3 years ago
11

Q3. Here are the first four terms of a sequence: 11, 22, 44, 88...

Mathematics
1 answer:
Orlov [11]3 years ago
4 0

Answer: a(n) = 11*2^(n-1)

a1 = 11

a2 = 22 = 11.2

a3 = 44 = 11.2²

a4 = 88 = 11.2³

......

=> this is a geometic with a1 = 11

                                           r = 2

=> a(n)=11.2^{n-1}

Step-by-step explanation:

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