The height of the isosceles triangle is 8.49 inches.
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How to find the height of the triangle?</h3>
Here we have a triangle such that two of the sides measure 9 inches, and the base measures 6 inches.
So this is an isosceles triangle.
We can divide the isosceles triangle into two smaller right triangles, such that the side that measures 9 inches is the hypotenuse, the base is 3 inches, and the height of the isosceles triangle is the other cathetus.
By Pythagorean's theorem, we can write:
(9in)^2 = (3 in)^2 + h^2
Where h is the height that we are trying to find.
Solving that for h we get:
h = √( (9 in)^2 - (3in)^2) = 8.49 inches.
We conclude that the height of the isosceles triangle is 8.49 inches.
If you want to learn more about triangles:
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Answer:
4
Step-by-step explanation:
If you add up 57+23=80 40+40=80 so 40 is the answer they will have the same amount Alice gets 40 and her sister gets 40
Answer:
The rectangle has a width of 4 and a height of 8
Step-by-step explanation:
Let the height of the rectangle be H and the width be W.
We know the height of the rectangle is twice the width, so:
H = 2W
The area of a rectangle, A, is given by A = W * H, so in this case:
32 = W * 2W
32 = 2W²
W² = 16
W = 4
Knowing that the width is 4, the height must be 8. This gives us an area of 32.
Answer:
Correct answer: sin x ⇒D(x) : [- π/2, π/2] ; sin⁻¹x ⇒ CD(x) : [- π/2, π/2]
Step-by-step explanation:
In order for the function sin x to have an inverse function sin⁻¹x due to the monotony, the domain is taken D(x) : [- π/2, π/2] and the range of sin⁻¹x is CD(x) : [- π/2, π/2].
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