The point at which the lines k(x) = 5x - 1 and h(x) = -3x - 1 meet is (0, -1)
Given: k(x) = 5x - 1, h(x) = -3x - 1
We need to find the point(if any) at which these two lines k and h meets.
To find point of intersection(if any), we need to set the functions equal as at the point of intersection the (x, y) value will be same for both of the lines.
Therefore, k(x) = h(x)
=> 5x - 1 = -3x - 1
=> 8x = 0
=> x = 0
k(x=0) = 5 * 0 - 1 = -1
Hence the point at which the lines k(x) = 5x - 1 and h(x) = -3x - 1 meet is (0, -1)
Know more about "point of intersection" problems here: brainly.com/question/16929168
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That will be radius * radius theeeeeen multiply it on the height
1) <span>30x4 − 20x3 + 15x2
This is the answer to 1. Don't forget to rearrange the terms in ascending order. That can trip people up.
2) </span><span>x3 + 8x2 + 13
Don't forget to check the terms sign. The subtraction symbol switches them all. </span>
Answer:
The anwser to this would be x=6 so C hope this helps :)
Answer:
(-11, -12)
Step-by-step explanation:
we need one variable to x out
on the note of x, lets cancel out the xs
6x+3y=-102
3x+y=-45 < same as 6x+2y-90
6x+3y=-102
-
6x+2y=-90
y=-12
substitute y in
3x-12=-45
3x=-33
x=-11
(-11, -12)
Please give brainliest :)
