Answer:
0, 2, 4, 6, 8, 10, etc..
Step-by-step explanation:
Basically any even number or 0
Answer:
jsnsjsnxnnxndkdkkddkkdncjdjx
add 4 each time
the nth term is a_n or f(n)
the next term after that is a_{n+1} or f(n+1)
so each term is 4 more than previous
basically
a_{n+1}=4+a_n or
f(n+1)=4+f(n)
same thing
In a throw of 2 fair dice, there are 6*6=36 equiprobability outcomes.
To get a sum of 5, there are 4 ways, (1,4),(2,3),(3,2),(4,1) with probability of 4/36=1/9
To get at least one 5, there are 6+6-1=11 outcomes (note (5,5) has been counted in both, so subtracted from sum). The probability is 11/36
Since the two events are mutually exclusive (once we have a five, the sum can no longer be 5), we can add the probabilities to get the probability of one event or the other.
P(sum of 5 OR at least one 5)=1/9+11/36=4/36+11/36=15/36=5/9
