Answer:
252 students at the party like to dance
Step-by-step explanation:
Given:
60% of the students are girls
40% of the students like to dance
20 more boy students
Percentage of the girls in the party = 58%
To Find:
How many students now at the party like to dance=?
Solution:
Let the number of girls be g.
Let the number of total people originally be t.
We know that
----------------------------------(1)
We also know that
![\frac{g}{t+20}=\frac{58}{100}](https://tex.z-dn.net/?f=%5Cfrac%7Bg%7D%7Bt%2B20%7D%3D%5Cfrac%7B58%7D%7B100%7D)
-----------------------------(2)
We now have a system of equation from (1) and (2)
3t=5g
------------------------(3)
50g=29t+580------------------------(4)
Substituting 3 in 4, we get
![50(\frac{3t}{5})=29t+580](https://tex.z-dn.net/?f=50%28%5Cfrac%7B3t%7D%7B5%7D%29%3D29t%2B580)
![(\frac{150t}{5})=29t+580](https://tex.z-dn.net/?f=%28%5Cfrac%7B150t%7D%7B5%7D%29%3D29t%2B580)
![30t =29t+580](https://tex.z-dn.net/?f=30t%20%3D29t%2B580)
![30t -29t = 580](https://tex.z-dn.net/?f=30t%20-29t%20%3D%20580)
t =589
So originally there was 580 students
In this 580 students 40% liked to dance
Then the number of students liked to dance =
=> ![40\% \text{of} 580](https://tex.z-dn.net/?f=40%5C%25%20%5Ctext%7Bof%7D%20580)
=>![\frac{40}{100} \times 580](https://tex.z-dn.net/?f=%5Cfrac%7B40%7D%7B100%7D%20%5Ctimes%20580)
=>![0.4 \times 580](https://tex.z-dn.net/?f=0.4%20%5Ctimes%20580)
=> 232
We also know that with these people, 20 boys joined, all of whom like to dance.
Now the number of students like to dance = 232+20 = 252 students