<span>So we want to know how much clay did Joseph add after he built the cone. So the formula for the volume of the cone is V=(1/3)*pi*r^2*h where r is the radius and h is height. We know h1=12cm and r1=6cm, r2=6cm and h2=18 cm. So to get the amount of added clay Va we simply subtract the volume of the clay of the first cone V1 from the volume of the second cone V2: Vd=V2-V1=(1/3)*pi*(r1^2)*h1 - (1/3)+pi*(r2^2)*h2. Va=678.24 cm^3-452.39 cm^3= 266.08 cm^3.</span>
Answer:
45
Step-by-step explanation:
Two tangents drawn to a circle from an outside point form arcs and an angle, and this formula shows the relation between the angle and the two arcs.
m<EYL = (1/2)(m(arc)EVL - m(arc)EHL) Eq. 1
The sum of the angle measures of the two arcs is the angle measure of the entire circle, 360 deg.
m(arc)EVL + m(arc)EHL = 360
m(arc)EVL = 360 - m(arc)EHL Eq. 2
We are given this:
m<EYL = (1/3)m(arc)EHL Eq. 3
Substitute equations 2 and 3 into equation 1.
(1/3)m(arc)EHL = (1/2)[(360 - m(arc)EHL) - m(arc)EHL]
Now we have a single unknown, m(arc)EHL, so we solve for it.
2m(arc)EHL = 3[360 - m(arc)EHL - m(arc)EHL]
2m(arc)EHL = 1080 - 6m(arc)EHL
8m(arc)EHL = 1080
m(arc)EHL = 135
Substitute the arc measure just found in Equation 3.
m<EYL = (1/3)m(arc)EHL
m<EYL = (1/3)(135)
m<EYL = 45
4 because you take 2²= 2 times 2 = 4
Answer:
Step-by-step explanation:
1.5(x + 4) - 3 = 4.5(x - 2)
1.5x + 6 - 3 = 4.5x - 9
1.5x + 3 = 4.5x - 9
3 + 9 = 4.5x - 1.5x
12 = 3x
12/3 = x
4 = x <======
