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zhenek [66]
3 years ago
13

Pls help I don't wanna get a bad grade make sure you show your work plz

Mathematics
2 answers:
tankabanditka [31]3 years ago
6 0

Answer:

the first one

Step-by-step explanation:

1. 1310 x 0.15 = 196.5

2. 1310 - 196.5 = 1113.5

3. 1113.5 - 310 = 803.5

4. 803.5 - 405 = 398.5

5. 398.5 divided by 2 = 199.25

Brut [27]3 years ago
3 0

Answer:797

Step-by-step explanation:the last one

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Tasya [4]

The angle of elevation of the sun from the ground to the top of a tree is 36°.

We are given that:

The sun from the ground to the top of a tree when a tree that is 10 yards tall casts a shadow 14 yards long.

Now by using the trigonometric identity .

tan θ = P / B

As figure is  given below .

AB =  Perpendicular = 10 yards

BC =  Base = 14 yards

Putting all the values in the trigonometric identity .

tan θ = 10 / 14

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Therefore, the angle of elevation of the sun from the ground to the top of a tree is 36°.

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1 year ago
Tony sells sporting goods. He makes a 10% commission on every dollar of sales that he makes. One month Tony got a commission che
I am Lyosha [343]

Answer:

He made $25,000 in total. A 10% is 1 tenth of the total. so multiply 2500 by 10.

Step-by-step explanation:

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Answer this volume based Question. I will make uh brainliest + 50 points​
Harlamova29_29 [7]

Answer:

\huge{\purple {r= 2\times\sqrt[3]3}}

\huge 2\times \sqrt [3]3 = 2.88

Step-by-step explanation:

  • For solid iron sphere:
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  • Formula for V_{sphere} is given as:

  • V_{sphere} =\frac{4}{3}\pi r^3

  • \implies V_{sphere} =\frac{4}{3}\pi (2)^3

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  • For cone:
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  • Let r = 3x & h = 4x

  • Formula for V_{cone} is given as:

  • V_{cone} =\frac{1}{3}\pi r^2h

  • \implies V_{cone} =\frac{1}{3}\pi (3x)^2(4x)

  • \implies V_{cone} =\frac{1}{3}\pi (36x^3)

  • \implies V_{cone} =12\pi x^3\: cm^3

  • It is given that: iron sphere is melted and recasted in a solid right circular cone of same volume
  • \implies V_{cone} = V_{sphere}

  • \implies 12\cancel{\pi} x^3= \frac{32}{3}\cancel{\pi}

  • \implies 12x^3= \frac{32}{3}

  • \implies x^3= \frac{32}{36}

  • \implies x^3= \frac{8}{9}

  • \implies x= \sqrt[3]{\frac{8}{3^2}}

  • \implies x={\frac{2}{ \sqrt[3]{3^2}}}

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  • \implies r= 2\times (3)^{1-\frac{2}{3}}

  • \implies r= 2\times (3)^{\frac{1}{3}}

  • \implies \huge{\purple {r= 2\times\sqrt[3]3}}
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  • log r = 0.4600704139

  • Taking antilog on both sides, we find:

  • antilog(log r )= antilog(0.4600704139)

  • \implies r = 2.8844991406

  • \implies \huge \red{r = 2.88\: cm}

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