4 years ago

How to find the vertex: i keep getting (-1,3) what am i doing wrong y=x^2+2x+6

1 answer:

3 0

You have the -1 correct but when (or if) you put it in the calculator then you have to put it in parentheses and you should get 5 so it would be (-1,5)

You might be interested in

12 Х 18 x= TO This is 7th grade math

svlad2 [7]

What’s the math called?

3 0

3 years ago

What is the poinet-slope form of the equation for the line in the graph?

Ne4ueva [31]

Answer:

$y -5 = \frac{9}{13}(x - 7)$

Step-by-step explanation:

Given :

Two points are given in graph (-6, -4) and {7, 5).

The point-slope form of the equation of a straight line is:

$y -y_{1} = m(x - x_{1})$ ------------(1)

Let $(x_{1}, y_{1})=(7,5)$ and $(x_{2}, y_{2})=(-6,-4)$

The slope of the line $m=\frac{y_{2}- y_{1}}{x_{2}- x_{1}}$

Put all known value in above equation.

$m=\frac{-4- 5}{-6- 7}$

$m=\frac{-9}{-13}$

$m=\frac{9}{13}$

The slope of the line $m=\frac{9}{13}$

We know m, and also know that $(x_{1}, y_{1})=(7,5)$ , so we put these value in equation 1.

$y -5 = \frac{9}{13}(x - 7)$

Therefore, the equation of the line is $y -5 = \frac{9}{13}(x - 7)$ .

6 0

3 years ago

About how many people had viewed the video once it had

leva [86]

Answer: 858

Step-by-step explanation:

5 0

3 years ago

What is the vertical asymptote for this function? y=1/x-2

nataly862011 [7]

Answer: x = 0

Step-by-step explanation: so x = 0 is the equation of the vertical asymptote, and 0 must be left out of the domain: (−∞,0)U(0,∞) in interval notation.

8 0

3 years ago

Is f(x)= 2x+x+3 a quadratic function?

yaroslaw [1]

Answer:

Step-by-step explanation:

6 0

4 years ago