2 years ago

Find the quotient: (X^3+ 8x^2+ 14x - 1)\ (x + 5) *not simplified completely solve pls

Mathematics

1 answer:

Liula [17]2 years ago

8 0

X^3 + 8x^2 + 14x - 1 / x+ 5
I believe this is all you can do

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2 years ago

If g(x)=4x-6 then g^-1(x)=?<br> (1) -4x+6<br> (2)-1/4x+1/6<br> (3)1/4x+3/2<br> (4)1/4x+6

kati45 [8]

Given:

$g(x)=4x-6$

To find:

The function $g^{-1}(x)$ .

Solution:

we have,

$g(x)=4x-6$

Put g(x)=y.

$y=4x-6$

Interchange x and y.

$x=4y-6$

Isolate y.

$x+6=4y$

$\dfrac{x+6}{4}=y$

$y=\dfrac{x+6}{4}$

Substitute $y=g^{-1}(x)$ .

$g^{-1}(x)=\dfrac{x+6}{4}$

$g^{-1}(x)=\dfrac{x}{4}+\dfrac{6}{4}$

$g^{-1}(x)=\dfrac{x}{4}+\dfrac{3}{2}$

Therefore, the correct option is (3).

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2 years ago

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<img src="https://tex.z-dn.net/?f=2x2%20-%2054%20%2B%2059" id="TexFormula1" title="2x2 - 54 + 59" alt="2x2 - 54 + 59" align="abs

Westkost [7]

The answer should be 4x+5

Please let me know if I’m wrong!

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2 years ago

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2 years ago