Kevin and Sam each have a map with the following instructions:

Each container must hold exactly 1 litre of water Each container must have a minimum surface area

Arada [10]

The containers must be spheres of radius = 6.2cm

<h3>How to minimize the surface area for the containers?</h3>

We know that the shape that minimizes the area for a fixed volume is the sphere.

Here, we want to get spheres of a volume of 1 liter. Where:

1 L = 1000 cm³

And remember that the volume of a sphere of radius R is:

$V = \frac{4}{3}*3.14*R^3$

Then we must solve:

$V = \frac{4}{3}*3.14*R^3 = 1000cm^3\\\\R =\sqrt[3]{ (1000cm^3*\frac{3}{4*3.14} )} = 6.2cm$

The containers must be spheres of radius = 6.2cm

If you want to learn more about volume:

brainly.com/question/1972490

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6 0

2 years ago

at an aquarium six out of 18 deliveries are plants out of 15 delivery's in one week how manybare plants

earnstyle [38]

Do six multiply fifteen which equals to 90

5 0

3 years ago

Zara is serving a fresh pie. She starts by cutting the pit in half, and then cuts each half into 4 equal pieces. What fraction o

Reptile [31]

C.

If each 1/2 is cut in 4 than you would have to multiply that by 2 because it's only half. Then since you're finding what fraction is it you would put a 1 on top and say 1/8.

7 0

4 years ago

Read 2 more answers

If a = 7 and b = 11, what is the measure of ∠B? (round to the nearest tenth of a degree) A) 32.5° B) 39.2° C) 50.5° D) 57.5°

Ilia_Sergeevich [38]

Answer:

D) 57.5°

Step-by-step explanation:

As the question is not complete. So, let's suppose it is a right angle triangle then, we can apply Pythagoras theorem to calculate the hypotenuse or the third side.

Pythagoras Theorem = $c^{2}$ = $a^{2} + b^{2}$

a = 7 and b = 11

$a^{2}$ = 49

$b^{2}$ = 121

Plugging in the values, we will get:

$c^{2}$ = 49 + 121

$c^{2}$ = 170

c = $\sqrt{170}$

To calculate the unknown angle B, we can use law of sine.

Law of sine = $\frac{a}{sinA}$ = $\frac{b}{sinB}$ = $\frac{c}{sinC}$

So,

$\frac{c}{sinC}$ = $\frac{b}{sinB}$

$\frac{\sqrt{170} }{sin90}$ = $\frac{11}{sinB}$

Sin90 = 1

sinB = $\frac{11}{\sqrt{170} }$

B = $sin^{-1}$ ( $\frac{11}{\sqrt{170} }$ )

B = 57.5°

8 0

3 years ago

The principal would like to assemble a committee of 4 students from the 16-member student council. How many different committees

mamaluj [8]

Answer:

4?

Step-by-step explanation:

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3 0

4 years ago