Answer:
RO
Step-by-step explanation:
Answer:
Draw an open circle at 4
Step-by-step explanation:
The answer is 62 with a remainder of 2.
Hope this helps!
Answer:
Null Hypothesis: H_0: \mu_A =\mu _B or \mu_A -\mu _B=0
Alternate Hypothesis: H_1: \mu_A >\mu _B or \mu_A -\mu _B>0
Here to test Fertilizer A height is greater than Fertilizer B
Two Sample T Test:
t=\frac{X_1-X_2}{\sqrt{S_p^2(1/n_1+1/n_2)}}
Where S_p^2=\frac{(n_1-1)S_1^2+(n_2-1)S_2^2}{n_1+n_2-2}
S_p^2=\frac{(14)0.25^2+(12)0.2^2}{15+13-2}= 0.0521154
t=\frac{12.92-12.63}{\sqrt{0.0521154(1/15+1/13)}}= 3.3524
P value for Test Statistic of P(3.3524,26) = 0.0012
df = n1+n2-2 = 26
Critical value of P : t_{0.025,26}=2.05553
We can conclude that Test statistic is significant. Sufficient evidence to prove that we can Reject Null hypothesis and can say Fertilizer A is greater than Fertilizer B.
5x+6y=18
5x=18-6y
x=(18-6y)/5
Use that in the other equation
18(18-6y)/5 - 15y = 36
64.8-21.6y - 15y = 36
28.8=36.6y
.7868=y
Now put that number in for y on the first equation
5x+6(.78) = 18
5x + 4.68 = 18
5x = 13.32
x = 2.66
and y = .78
