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Damm [24]
2 years ago
12

Find the surface area of this triangular prism. Please explain as well, I’m struggling with it.

Mathematics
2 answers:
Ierofanga [76]2 years ago
7 0

Answer:

84 cm^{2}

Step-by-step explanation:

To find the surface area of a prism, one will have to find the area of each of the sides of the prism, then add the areas up. First, find the dimensions of each of the sides

Front; 5 x 6

Front triangle; 3 x 4

Back triangle; 3 x 4

Bottom; 4 x 6

Back; 3 x 6

The front is a rectangle, hence one has to base * height to find the area;

5 x 6

= 30

The front triangle is a triangle, hence on has to do \frac{base * height}{2} to find the area;

\frac{3*4}{2}

= 6

The back triangle is a triangle, hence on has to do \frac{base * height}{2} to find the area;

\frac{3*4}{2}

= 6

The back is a rectangle, so one has to do base * height to find the area;

4 * 6

= 24

The bottom is a rectangle,  o one has to do base * height to find the area;

3 * 6

= 18

Noe one has to add up all the areas to find the total surface area;

Front + Front_triangle + Back_triangle + Bottom + Back

30 + 6 + 6 + 24 + 18

= 84

scZoUnD [109]2 years ago
3 0

Answer:

SA= 84 cm^2

Step-by-step explanation:

So first locate all the surfaces

we got 5 sides in total

Now calculate each one

Lets start with the 2 triangles

so formula for area of triangl is 1/2(b*h)

So in this case it’s 6

Now there are 2 identical triangles

So Times the 6 by 2

You’ll get 12

Thats 2 sides

Now for the side with the rectangle of 5cm and 6cm

Area of rectangle is 5*6=30

That would onay be 1 side

Now for the bottom of the prisim which is the side with 4cm and 6cm

Same rectangle so multiply

4*6=24

Thats another side down

The last side is on the left with the back not visible. The two dimensions are 6 and 3

Now multiply 6*3

18

Now add up your total

18+24+12+30=84

So 84 cm^2 OR 84 square centimeters

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3 years ago
A string passing over a smooth pulley carries a stone at one end. While its other end is attached to a vibrating tuning fork and
nasty-shy [4]

Answer:

correct option is C)  2.8

Step-by-step explanation:

given data

string vibrates form =  8 loops

in water loop formed =  10 loops

solution

we consider  mass of stone = m

string length = l

frequency of tuning = f

volume = v

density of stone = \rho

case (1)  

when 8 loop form with 2 adjacent node is \frac{\lambda }{2}

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l = \frac{8 \lambda _1}{2}      ..............1

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\sqrt{\frac{mg}{\mu}}   =   f × \lambda_1     ..........................3

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l = 5 \lambda_1\\\\\lambda_1 = \frac{l}{5}

when block is immersed

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Tenion + force of buoyancy = mg

T + v × \rho × g = mg

and

T = v × \rho - v × \rho × g    

from equation 2

f × \lambda_2 = f  × \frac{1}{5}  

\sqrt{\frac{v\rho _{stone} g - v\rho _{water} g}{\mu}} = f \times \frac{1}{5}     .......................5

now we divide eq 5 by the eq 3

\sqrt{\frac{vg (\rho _{stone} - \rho _{water})}{\mu vg \times \rho _{stone}}} = \frac{fl}{5} \times \frac{4}{fl}

solve irt we get

1 - \frac{\rho _{stone}}{\rho _{water}}  = \frac{16}{25}

so

relative density \frac{\rho _{stone}}{\rho _{water}} = \frac{25}{9}

relative density = 2.78 ≈ 2.8

so correct option is C)  2.8

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