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Gennadij [26K]
3 years ago
13

Which metric unit would be best to measure the width of a room?

Mathematics
1 answer:
STatiana [176]3 years ago
8 0

Most household objects such as tables, rooms, window frames, television screens, etc. would be measured in meters. Kilometers are used to measure long distances. If you are looking to figure out the length of a road, the distance between two locations, etc, you would use kilometers.

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A. 3/22 <br> B. 3/7<br> C. 8/15<br> D. 8/11
lorasvet [3.4K]
P(Q|R) = P(Q&R)/P(R)
= (3/37)/(7/37)
= 3/7

The appropriate choice is ...
  B. 3/7
6 0
3 years ago
Plzzz help me im having alot of trouble understanding this question does some one understand if you do plz help fast!!!
juin [17]

Answer:

1/2 - 3(1/2 + 1)²

simplify the expression (1/2 + 1)

1/2 - 3•(3/2)²

using PEMDAS, we see we have to evaluate the exponent first

(3/2)² = 9/4

rewrite the equation

1/2 - 3 • (9/4)

multiply 3 by (9/4)

1/2 - (27/4)

subtract

-25/4

(1 + 1/3)² - 2/9

simplify the expression (1 + 1/3)

(4/3)² - 2/9

using PEMDAS, we see we have to evaluate the exponent first

(4/3)² = 16/9

rewrite the equation

(16/9) - (2/9)

subtract

14/9

5 0
3 years ago
Where is the center of CD given C(-6, 12) and D (13, 20)?
Law Incorporation [45]
(3.5, 16)

Midpoint Formula is 
((x1+x2)/2, (y1+y2)/2)
3 0
3 years ago
Three circular arcs of radius units bound the region shown. Arcs and are quarter-circles, and arc is a semicircle. What is the a
mestny [16]

Answer:

Three circular arcs of radius $5$ units bound the region shown. Arcs $AB$ and $AD$ are quarter-circles, and arc $BCD$ is a semicircle.

Step-by-step explanation:

8 0
2 years ago
Find the distance from the origin to the graph of 6x+3y+2=0
AURORKA [14]
Slope=-2
Y-intercept—2/3
5 0
3 years ago
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