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2 years ago

12

This table shows the linear relationship of the water level in a tank and time.

1 answer:

Serga [27]2 years ago

3 0

Step-by-step explanation:

according to the table, the rate of change of the water level =

(40-50)/(2-0)

= -10/2

= -5 ft/hr

You might be interested in

Hhellp pwease I want to know what's wrong and right

Studentka2010 [4]

Answer:

A: False

B: False

C: True

D: True

E: False

F: True

G: True

H: True

Step-by-step explanation:

A: 9(x - 2) = 9x + 2

9x - 18 = 9x + 2 FALSE

B: 65 - y = y - 65

(equation rearranged) -y + 65 = y - 65 FALSE

C: g (times) h = h (times) g (TRUE due to the commutative property of multiplication)

D: a (times) 0 = 0 (TRUE because anything times 0 equals 0)

E: (4 (times) 2) - r = 4 (2 (times) r)

8 - r = 8 - 4r FALSE

F: k + 0 = k TRUE

G: (a + x) + y = a + (x + y)

a + x + y = a + x + y TRUE

H: 5(2x - 9) = 10x - 45

10x - 45 = 10x - 45 TRUE

6 0

3 years ago

The Municipal Transit Authority wants to know if, on weekdays, more passengers ride the northbound blue line train towards the c

Kitty [74]

Answer:

The 90% confidence interval $-49.8$

The null hypothesis is $H_o : \mu_1 = \mu_2$

The alternative hypothesis $H_a : \mu_1 < \mu_2$

The distribution test statistics is $t = -3.222$

The rejection region is p-value < $\alpha$

The decision rule is reject the null hypothesis

The conclusion is

There is sufficient evidence to conclude that there are more passengers riding the 8:30 train

The p-value is $p-value =0.000951$

Step-by-step explanation:

From the question we are told that

The first sample size $n_1 = 30$

The first sample mean is $\= x _1 = 323$

The first standard deviation is $s_1 = 41$

The second sample size is $n_2 = 45$

The second sample mean is $\=x_2 = 356$

The second standard deviation is $s_2 = 45$

given that the confidence level is 90% then the level of significance is mathematically represented as

$\alpha = (100 -90)\%$

$\alpha = 0.10$

Generally the critical value of $\frac{\alpha }{2}$ obtained from the normal distribution table is

$Z_{\frac{\alpha }{2} } = 1.645$

Generally the pooled variance is mathematically represented as

$s^2 = \frac{(n_1 - 1)s_1^2 + (n_2 -1)s_2^2 }{n_1 + n_2 -2}$

$s^2 = \frac{(30 -1)(41^2) + (45-1)45^2}{30+45 -2}$

$s^2 = 1888.34$

Generally the standard error is mathematically represented as

$SE = \sqrt{\frac{s^2}{n_1} + \frac{s^2}{n_2} }$

=> $SE = \sqrt{\frac{1888.34}{30} + \frac{1888.34}{45} }$

=> $SE = 10.24$

Generally the margin of error is mathematically evaluated as

$E = Z_{\frac{\alpha }{2} } * SE$

$E = 1.645* 10.24$

$E = 16.85$

Generally the 90% confidence interval is mathematically represented as

$\=x_1 -\=x_2 -E < \mu_1 -\mu_2 < \=x_1 -\=x_2 +E$

$323 -356 -16.84$

$-49.8$

The null hypothesis is $H_o : \mu_1 = \mu_2$

The alternative hypothesis $H_a : \mu_1 < \mu_2$

Generally the test statistics is mathematically represented as

$t = \frac{\= x_1 - \=x_2 }{SE}$

=> $t = \frac{323-356}{10.24}$

=> $t = -3.222$

Generally the degree of freedom is mathematically represented as

$df = n_1+n_2 -2$

$df = 30 + 45 -2$

$df = 73$

The p-value is obtained from the student t distribution table at degree of freedom of 73 at 0.05 level of significance

The value is $p-value =0.000951$

Here the level of significance is $\alpha = 5\% = 0.05$

Given that the p-value < $\alpha$ then we reject the null hypothesis

Then the conclusion is

There is sufficient evidence to conclude that there are more passengers riding the 8:30 train

5 0

3 years ago

How do you solve (5^{2} - 1) ÷ 6

posledela

$( {5}^{2} - 1) \div 6 =$

$(25 - 1) \div 6 =$

$24 \div 6 = 4$

Note:

Do the square first, and then you do mathematic operation between the parentheses. And, then do the

mathematic operation in the outside of parentheses.

Thank you.

8 0

3 years ago

Read 2 more answers

What is the correct solution to 1/2(x+18)=4(2x-6)-9x

denis-greek [22]

Answer:

x = 22

Step-by-step explanation:

I interpreted your problem as:

$\frac{1}{2} (x+18) = 4(2x-6)-9x$

I simplified the problem to:

$\frac{1}{2} x+9 = 8x-24-9x$

I combined like terms:

$\frac{1}{2} x+9 = -x-24$

I moved all x to one side and all other constants to the other:

$\frac{3}{2} x = -33$

I divided by 3/2 (1.5) on both sides to isolate x:

$x = 22$

Hope it helps! (:

4 0

3 years ago

ASAP! BRAINLIEST!

nasty-shy [4]

Answer:

The average rate of change from 3 to 6 storms = 0.04

Step-by-step explanation:

Let number of Storms = N

And Predicted Gas Price = P

it is required to find the average rate of change from 3 to 6 storms.

At N = 3 ⇒ P = $2.44

At N = 6 ⇒ P = $2.56

So, the average rate of change = $\frac{2.56-2.44}{6-3}=\frac{0.12}{3}=0.04$

5 0

3 years ago