Question

Solve the system: 2x+6y=36 x+4y=20

Answer 1

Let's solve this problem step-by-step

Let's set:

   2x + 6y = 36 -- equation 1

   x + 4y = 20 -- equation 2

(equation 2) * 2

   2x + 8y = 40 -- equation 3

(equation 3) - (equation 1)

   2y = 4

   y = 2 -- equation 4

Plug (equation 4)'s value of y into (equation 2)

   x + 4(2) = 20

   x = 20 - 8

   x = 12

Thus x = 12 and y = 2

Let's check, by substituting these values

  $2x + 6y = 36\\2(12)+6(2) = 36\\24+12=36\\36=36\\\\x+4y=20\\12+4(2)=20\\12+8=20\\20=20$

Answer: x = 12 and y = 2

Hope that helps!