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1 year ago

Solve the system: 2x+6y=36 x+4y=20

Mathematics

1 answer:

Assoli18 [71]1 year ago

5 0

Let's solve this problem step-by-step

Let's set:

2x + 6y = 36 -- equation 1

x + 4y = 20 -- equation 2

(equation 2) * 2

2x + 8y = 40 -- equation 3

(equation 3) - (equation 1)

2y = 4

y = 2 -- equation 4

Plug (equation 4)'s value of y into (equation 2)

x + 4(2) = 20

x = 20 - 8

x = 12

Thus x = 12 and y = 2

Let's check, by substituting these values

$2x + 6y = 36\\2(12)+6(2) = 36\\24+12=36\\36=36\\\\x+4y=20\\12+4(2)=20\\12+8=20\\20=20$

Answer: x = 12 and y = 2

Hope that helps!

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Answer:

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2 years ago

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Answer:

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Step-by-step explanation:

Hi there! I'm glad I was able to help you solve this equation!

Let's start by simplifying both sides of the equation. It's easier to solve it this way!

$v - 6 (4v + 6) = -82$

Distribute:

$v + (-6) (4v) + (-6) (6) = -82$

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Combine 'like' terms:

$(v -24v) + (-36) = -82$

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Next, you'll want to add 36 to both sides of the equation.

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Finally, divide both sides by $-23$ .

$\frac{-23v}{-23} = \frac{-46}{-23}$

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I hope this helped you! Leave a comment below if you have any further questions! :)

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