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goldfiish [28.3K]
3 years ago
12

What statement are true about this expression 2/3n +58.6

Mathematics
1 answer:
vampirchik [111]3 years ago
6 0

Step-by-step explanation:

perdon no entindo

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Help help help help help ASAP
Rufina [12.5K]

Answer:

No, it is much too low

5 0
3 years ago
Describe how to write 7,594,000,000 in scientific notation. Complete the description. First move the decimal point places to the
s2008m [1.1K]

Step-by-step explanation:

The given number is 7,594,000,000.

To convert it into scientific notation,

First move the decimal point places to the left to find a number that is greater than or equal to 1 and less than 10. Then multiply by 10 , using an exponent on 10 that equals the number of places you moved the decimal. The exponent is negative if the original no was <1 and the exponent is positive, if the original number was  > 1.

In 7,594,000,000, we move the decimal point places to the left before 5. It means we have moved 9 digits left.

Hence, 7,594,000,000=7.59\times 10^9 is the scientific notation.

6 0
3 years ago
The product of a number and nine is added to five. The result is thirty-
Nuetrik [128]

Answer:

The number is 11

Step-by-step explanation:

6x+38=9x+5

3x=33

x= 11

5 0
3 years ago
A delivery truck is transporting boxes of two sizes: large and small. The large boxes weigh 50 pounds each, and the small boxes
skad [1K]
So this is how we are going to solve for the given problem above.
Given that x = number of large boxes
and 120-x = number of small boxes.
So here is the solution:
50x + (120-x)20 = 4050
50x + 2400 - 20x = 4050
30x + 2400 = 4050
30x = 4050 - 2400
30x = 1650 <<divide both sides by 30
x = 55.
Therefore, there are 55 large boxes
120 - x = small boxes
120 - 55 = 65 small boxes.
Hope this is the answer that you are looking for.
Let me know if you need more help next time!

6 0
3 years ago
Simplify 4 to the 7th over 5 squared all raised to the 3rd power.
DIA [1.3K]
((4^7)/(5^2))^3 I'm pretty sure this is how you would right the problem to begin with
3 0
3 years ago
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