Answer:
t = 4 seconds
Step-by-step explanation:
The height of the projectile after it is launched is given by the function :
t is time in seconds
We need to find after how many seconds will the projectile land back on the ground. When it land, h(t)=0
So,
The above is a quadratic equation. It can be solved by the formula as follows :
Here, a = -16, b = 32 and c = 128
Neglecting negative value, the projectile will land after 4 seconds.
Answer:
y= 1/4,1/2,1,2,4,8,16,32,64
Step-by-step explanation:
Make negative powers positive by turning them into a fraction so is really
=
so
is just
. then
=1 [any number to the zero power is = 1],
2^1 = 2, 2^2=4, 2^3=8, 2^4=16, 2^5=32, 2^6 = 2x2x2x2x2x2=64
Answer: 60°
<u>Step-by-step explanation:</u>
∠UQR = 180°
∠UQR = ∠UQ + ∠QR
180° = 115° + ∠QR
65° = ∠QR
∠QRT = 180°
∠QRT = ∠QR + ∠RS + ∠ST
180° = 65° + ∠RS + 55°
180° = 120° + ∠RS
60° = ∠RS
