Answer:
n = -14
Step-by-step explanation:
when multiplying bases, add their exponents
Answer:
The ira will contain $228,278.05 when he retires at age 65. This is 6.04 times the amount of money he deposited.
Step-by-step explanation:
In order to solve this problem, we can make use of the following formula:
![FV=PMT[\frac{(1+i)^{n}-1}{i}]](https://tex.z-dn.net/?f=FV%3DPMT%5B%5Cfrac%7B%281%2Bi%29%5E%7Bn%7D-1%7D%7Bi%7D%5D)
Where:
FV= Future value of the ira
PMT= the amount of money you deposit each month
i= is the interest rate per period
n=number of periods
in this case we will assume the interest will be compounded each month.
So:
FV this is what we need to know.
PMT= $75 the amount he will deposit each month
t = 42 years,
this is 65-23=42
n=42 years * 12 months/year = 504 months
i=0.07/12
So we can now use the given formula:
![FV=PMT[\frac{(1+i)^{n}-1}{i}]](https://tex.z-dn.net/?f=FV%3DPMT%5B%5Cfrac%7B%281%2Bi%29%5E%7Bn%7D-1%7D%7Bi%7D%5D)
![FV=75[\frac{(1+\frac{0.07}{12})^{504}-1}{\frac{0.07}{12}}]](https://tex.z-dn.net/?f=FV%3D75%5B%5Cfrac%7B%281%2B%5Cfrac%7B0.07%7D%7B12%7D%29%5E%7B504%7D-1%7D%7B%5Cfrac%7B0.07%7D%7B12%7D%7D%5D)
So we get:
FV=$228,278.05
which is the amount of money he will have after 42 years.
In total, he deposited:
$75*504months = $37,800
so he will have:
times the amount of money he deposited throughout this time.
9.6973 will be your answer
Answer:
t = 39
Step-by-step explanation:
the diagonals of a parallelogram bisect each other, therefore t = 3t - 78 further solving this equation we get
2t = 78 and then t = 39
Answer:
Step-by-step explanation:
Let's solve your system by substitution.
2x+3y=15;x+y=6
Rewrite equations:
x+y=6;2x+3y=15
Step: Solvex+y=6for x:
x+y=6
x+y+−y=6+−y(Add -y to both sides)
x=−y+6
Step: Substitute−y+6forxin2x+3y=15:
2x+3y=15
2(−y+6)+3y=15
y+12=15(Simplify both sides of the equation)
y+12+−12=15+−12(Add -12 to both sides)
y=3
Step: Substitute3foryinx=−y+6:
x=−y+6
x=−3+6
x=3(Simplify both sides of the equation)
Answer:
x=3 and y=3