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tino4ka555 [31]
3 years ago
12

Someone, please help me

Mathematics
1 answer:
Soloha48 [4]3 years ago
4 0
I think the answer is pumpkin 1
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Please help me with this question
SIZIF [17.4K]
-3/4x+6 < A < 4x
hope this helps
6 0
2 years ago
Solve the variable<br> -10+ s/1.5= -5
patriot [66]

Answer:

s = 15 over 2 (15/2 fraction) or 7.5

3 0
3 years ago
Write a rule for the nth term of the sequence. Then find a20. Assume the first termis a₁. 86, 79, 72, 65…
hodyreva [135]

Answer:

an = a(n-1) - 7

Step-by-step explanation:

the second term is smaller than the first term 7.

a20 = a19 - 7

a19 = a18 - 7

=> a20 = (a18 - 7) - 7

Then you can accumalate until a1

-> a20 = a1 - 19*7 = 86 - 19*7 = -47

5 0
3 years ago
In what year will the two quantities be​ equal?
Galina-37 [17]

Its the second because i did this already

3 0
4 years ago
A certain mathematics contest has a peculiar way of giving prizes. Five people are named as Grand Prize winners, but their finis
bixtya [17]

Answer:

The number of complete award announcements possible are 19,554,575,040.

Step-by-step explanation:

Combination is the number of ways to select <em>k</em> items from <em>n</em> distinct items when the order of selection does not matters.

Whereas permutation is the number of ways to select <em>k</em> item from <em>n</em> items when order of selection matters.

The number of people entering this year is 22.

The number of ways to select 5 people for Grand Prize is, {22\choose 5}=\frac{22!}{5!(22-5)!} =26334.

The remaining number of people is, 22 - 5 = 17.

It is provided that the other 5 are selected according to an order.

The number of ways to select other 5 winners is,

^{17}P_{5}=\frac{17!}{(17-5)!} =742560

The total number of ways to select 10 winners of 22 is:

Total number of ways = 26334 × 742560 = 19,554,575,040.

6 0
3 years ago
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