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taurus [48]
3 years ago
8

Use the graph to state the solution for the system.

Mathematics
1 answer:
Alenkasestr [34]3 years ago
4 0
Your answer would be (3,0)
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Write an expression for the measurement of angle L using the measurement of angle C found in part C
kap26 [50]

Answer:

180’ - 130’

Step-by-step explanation:

3 0
3 years ago
Which is bigger? 2^4 or 4^2?​
vovikov84 [41]

Answer:

Both are equal

Step-by-step explanation:

2^4 = 16 \\  \\  {4}^{2}  = 16 \\  \\ \implies \:  {2}^{4}  =  {4}^{2}

8 0
3 years ago
Read 2 more answers
A rectangular garden has vertices at (4, 3), (6, 3), (6, 9), and (4, 9). Plot each vertex of the garden.
kati45 [8]

Answer:

Step-by-step explanation:

A rectangular garden has vertices at

(x = 4, y = 3), (x = 6, y = 3), (x = 6, y = 9), and (x = 4, y = 9).

To plot each vertex of the garden find on the graph the x and y coordinate of the point and mark the point.

3 0
2 years ago
Given that −4i is a zero, factor the following polynomial function completely. Use the Conjugate Roots Theorem, if applicable. f
GalinKa [24]

Answer:

\large \boxed{\sf \bf \ \ f(x)=(x-4i)(x+4i)(x+3)(x-5) \ \ }

Step-by-step explanation:

Hello, the Conjugate Roots Theorem states that if a complex number is a zero of real polynomial its conjugate is a zero too. It means that (x-4i)(x+4i) are factors of f(x).

\text{Meaning that } (x-4i)(x+4i) =x^2-(4i)^2=x^2+16 \text{ is a factor of f(x).}

The coefficient of the leading term is 1 and the constant term is -240 = 16 * (-15), so we a re looking for a real number such that.

f(x)=x^4-2x^3+x^2-32x-240\\\\ =(x^2+16)(x^2+ax-15)\\\\ =x^4+ax^3-15x^2+16x^2+16ax-240

We identify the coefficients for the like terms, it comes

a = -2 and 16a = -32 (which is equivalent). So, we can write in \mathbb{R}.

\\f(x)=(x^2+16)(x^2-2x-15)

The sum of the zeroes is 2=5-3 and their product is -15=-3*5, so we can factorise by (x-5)(x+3), which gives.

f(x)=(x^2+16)(x^2-2x-15)\\\\=(x^2+16)(x^2+3x-5x-15)\\\\=(x^2+16)(x(x+3)-5(x+3))\\\\=\boxed{(x^2+16)(x+3)(x-5)}

And we can write in \mathbb{C}

f(x)=\boxed{(x-4i)(x+4i)(x+3)(x-5)}

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

7 0
3 years ago
For the function f(x)=3(x-1)^2+2, identify the vertex,domain, and range -The vertex is (1,2), the domain is all real numbers, an
sdas [7]

Answer:

The function is...f(x)=(-1,-2)

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
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