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zlopas [31]
3 years ago
15

Help pls no linksill give you briliantest ​

Mathematics
1 answer:
Aneli [31]3 years ago
5 0

Answer:

W=20

A=400

Step-by-step explanation:

90+310 for area

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4X+8&lt;28<br> ayudenme por favor
VMariaS [17]

Answer:

x < 5.

Step-by-step explanation:

Creo que esto es correcto. :')

7 0
2 years ago
Please help me out with this!
Evgen [1.6K]

<u>Answer is;</u>

b

<u>explanation</u>

midpoint of two points is given by;

{(x1+x2)/2},{(y1+y2)/2}.

midpoint of QS={(2a+2b)/2},{(0+2c)/2}

= {a+b},{c}

5 0
3 years ago
Using the segment addition postulate, which is true? What is the measure of AngleDCF? Three lines extend from point C. The space
Flura [38]

Answer:

129

Step-by-step explanation:

If three lines CD, CE and CF extend from point C, then the following addition postulate is true;

<DCE + <ECF = <DCF

If the space between line C D and C E is 75 degrees, then <DCE =  75

If the space between lines C E and C F is 54, then <ECF = 54.

Substitute the given values into the expression above will  give;

<DCF =<DCE + <ECF

<DCF  = 75+54

<DCF  = 129

Hence the measure of <DCF  is 129°

8 0
3 years ago
Which is the solution set to the given inequality |x+3|&lt;12? x infinity(-15,9), x infinity {-15,9], x infinity (00,-15)U(9,00)
Viefleur [7K]

Answer:

Part 1) The solution set is (-15,∞) ∩ (-∞,9)=(-15,9)

Part 2) The ordered pair (1,3) is a solution of the system

Step-by-step explanation:

Part 1) we have

\left|x+3\right|

<u>First solution case Positive</u>

+(x+3)

x

x

The solution first case is the interval -------> (-∞,9)

<u>Second solution case Negative</u>

-(x+3)

-x-3

-x

-x ------> Multiply by -1 both sides

x>-15

The solution second case is the interval -------> (-15,∞)

The solution set is equal to

(-15,∞) ∩ (-∞,9)=(-15,9)  

Part 2) we have

y>-2 -------> inequality A

x+y\leq 4 -----> inequality B

we know that

If a ordered pair is a solution of the system of inequalities, then the ordered pair must satisfy both inequalities

Verify each case

case a) (1,5)

Substitute the value of x and the value of y in the inequality and then compare

<u>Inequality A</u>

5>-2 ------> is true

<u>Inequality B</u>

1+5\leq 4

6\leq 4 -----> is not true

therefore

the ordered pair is not a solution

case b) (0,5)

Substitute the value of x and the value of y in the inequality and then compare

<u>Inequality A</u>

5>-2 ------> is true

<u>Inequality B</u>

0+5\leq 4

5\leq 4 -----> is not true

therefore

the ordered pair is not a solution

case c) (-2,-3)

Substitute the value of x and the value of y in the inequality and then compare

<u>Inequality A</u>

-3>-2 ------> is not true

therefore

the ordered pair is not a solution

case d) (1,3)

Substitute the value of x and the value of y in the inequality and then compare

<u>Inequality A</u>

3>-2 ------> is true

<u>Inequality B</u>

1+3\leq 4

4\leq 4 -----> is true

therefore

the ordered pair is  a solution

6 0
3 years ago
How do you graph y=3x^2
Rainbow [258]
So because it's x^2 that means it's a parabola. The 3 before it is it's stretch factor (slope, so instead of going over one up one it goes over one up 3)

8 0
3 years ago
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