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liq [111]
2 years ago
15

Find the mean of the following data set 73, 81, 51, 76, 89, 95, 88

Mathematics
2 answers:
kifflom [539]2 years ago
6 0

Answer:

mean =  \frac{(73 + 81 + 51 + 76 + 89 + 95 + 88)}{7}  \\  = 79

Darya [45]2 years ago
6 0

Answer:

79

Step-by-step explanation:

What is mean?  The mean is the same as an average. To find the mean, add all the letters together. Then, divide this sum by the total amount of numbers.

Step One: 73+ 81+51 +76+ 89+ 95+88= 553

Step Two: Divide by numbers, in this case, there are 7: 553/7= 79.

There you go!

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3 0
2 years ago
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Six sophomores and 14 freshmen are competing for two alternate positions on the debate team. Which expression represents the pro
Elanso [62]

Answer:

<em>Choose the first alternative</em>

\displaystyle P=\frac{_{1}^{6}\textrm{C}\ _{1}^{5}\textrm{C}}{_{2}^{20}\textrm{C}}

Step-by-step explanation:

<u>Probabilities</u>

The requested probability can be computed as the ratio between the number of ways to choose two sophomores in alternate positions (N_s) and the total number of possible choices (N_t), i.e.

\displaystyle P=\frac{N_s}{N_t}

There are 6 sophomores and 14 freshmen to choose from each separate set. There are 20 students in total

We'll assume the positions of the selections are NOT significative, i.e. student A/student B is the same as student B/student A.

To choose 2 sophomores out of the 6 available, the first position has 6 elements to choose from, the second has now only 5

_{1}^{6}\textrm{C}\ _{1}^{5}\textrm{C} \text{ ways to do it}

The total number of possible choices is

_{2}^{20}\textrm{C} \text{ ways to do it}

The probability is then

\boxed{\displaystyle P=\frac{_{1}^{6}\textrm{C}\ _{1}^{5}\textrm{C}}{_{2}^{20}\textrm{C}}}

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