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olga_2 [115]
3 years ago
7

Find the measure of each acute angle.

Mathematics
2 answers:
Rudik [331]3 years ago
7 0
X =5 so 11x-2=53 and 6x+7=37
Kruka [31]3 years ago
3 0

Answer:

11x-2 is 53 degrees and the other one is 37

Step-by-step explanation:

(11x-2)+(6x+7)=90 degrees 17x plus 5 is 90 and 90 minus is 85 and 85/17 is 5 and plug it back into the equations

You might be interested in
Suppose a manufacturer finds that 95% of their production is normal but the final 5% has one or more flaws. Each flawed good has
RUDIKE [14]

Answer:

1)    

FLAW                         TYPE2         NO TYPE2 FLAW

TYPE1                         0.015           0.025

NO TYPE1 FLAW        0.01             0.95

2) 0.04 and $0.04

3) 0.025 and $0.025

4) 0.015 and $0.015

5) 0.95 and $0.95

Step-by-step explanation:

Given that;

financial cost = $1

p(flaw) = 0.05  

p(type 1 flaw / flaw) = 80% = 0.8

p(type 2 flaw / flaw) = 50% = 0.5

p( type 1 and 2 flaw/flaw) = 30% = 0.30

1) Bivariate Table

p( type 1 flaw) = p(flaw) × p(type 1 flaw/flaw) = 0.05 × 0.8 = 0.04

p( type 2 flaw) = p(flaw) × p(type 2 flaw/flaw)  = 0.05 × 0.5 = 0.025

p( type 1 and 2 flaw) =  p(flow) × p( type 1 & 2 flaw/flaw) = 0.05 × 0.3 = 0.015

p( only 1 flow) = 0.04 - 0.015 = 0.025

p( only 2 flow) =  0.025 - 0.015 = 0.01

THEREFORE  the Bivariate Table;

FLAW                         TYPE2         NO TYPE2 FLAW

TYPE1                         0.015           0.025

NO TYPE1 FLAW       0.01              0.95

2) probability and expectations of type 1 flaw?

p( type 1 flaw) = p(flaw) × p(type 1 flaw/flaw) = 0.05 × 0.8 = 0.04

Expected financial cost to the firm per good = $1 × 0.04 = $0.04

3)  probability and expectation of Type 2 flaw

p( type 2 flaw) = p(flaw) × p(type 2 flaw/flaw)  = 0.05 × 0.5 = 0.025

Expected financial cost to the firm per good = $1 × 0.025 = $0.025

4) probability and expectations of Type 1 and 2 flaws

p( type 1 and 2 flaw) =  p(flow) × p( type 1 & 2 flaw/flaw) = 0.05 × 0.3 = 0.015

Expected financial cost to the firm per good = $1 * 0.015 = $0.015

5) probability and expectations of no flaws?

Probability of no flaw = P(No flaw) =95% =  0.95

Expected financial cost saved the firm per good due to no flaw

= $1 × 0.95 = $0.95

5 0
4 years ago
−8 3/4÷2 1/6 please show me ur work
nalin [4]

Answer:

  • - 4 1/26

Step-by-step explanation:

<u>Solving in steps:</u>

  • - 8 3/4 ÷ 2 1/6 =
  • - 35/4 ÷ 13/6 =
  • - 35/4 × 6/13 =
  • - 35/2 × 3/13 =
  • - 105/26 =
  • - 4 1/26
6 0
3 years ago
Four students are competing in a spelling bee. The top three students will receive a medal. How many different ways can they fin
Gre4nikov [31]

Answer:

<em>How many different ways can the letters of the word MATH be rearranged to form a four- ... 4 · 3 · 2 · 1 = 24 ways to spell a code worth with the letters MATH. ... example, coming in first means that you get the gold medal instead of the ... A group of four students is to be chosen from a 35-member class to represent the class.</em>

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
I Need help with 4-7
Murrr4er [49]

Answer:

Step-by-step explanation:

4) parallel because 118° is a supplement to 62° and the corresponding angles are both 118°

5) NOT parallel. The labeled angles sum to 120° and would sum to 180° for parallel lines.

6) NOT parallel. see pic.

If parallel, extending a line to intersect ℓ₁ makes an opposite internal angle which would also be 48°. The created triangle would have its third angle at 180 - 90 - 48 = 42° which is opposite a labeled 48° angle, which is false, so the lines cannot be parallel

7)

b = 78°  as it corresponds with a labeled angle above it

a = 180 - 78 = 102° as angles along a line from a common vertex sum to 180

f = is an opposite angle to 180 - 78 - 44 = 58° as angles along a line from a common vertex sum to 180

e = 180 - 90 - 64 = 26° as angles along a line from a common vertex sum to 180

c = 58° as it corresponds with f

d = 180 - 58 = 122° as angles along a line from a common vertex sum to 180

 

4 0
3 years ago
The distance y in miles traveled by a striped marlin in x hours is shown in the graph. Each ocean creature’s distance in miles i
julsineya [31]

9514 1404 393

Answer:

  swordfish

Step-by-step explanation:

The graph shows the marlin travels 50 miles in 1 hour, and 150 miles in 3 hours. These numbers can be compared directly to those given for the tuna (43.5 miles in 1 hour) and the wahoo fish (144 miles in 3 hours).

The speeds of the swordfish and shark are the coefficients of x in their respective equations. The swordfish travels 60 mph, so is faster than the marlin. The shark travels 31 mph, so is slower.

7 0
3 years ago
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