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Gemiola [76]
2 years ago
10

La suma de un numero mas 16 es igual a 31

Mathematics
1 answer:
Simora [160]2 years ago
8 0

Answer:

47

Step-by-step explanation:

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The answer to the problem i asked
guapka [62]
8(4x+5)=136
Multiply the number outside of the parenthesis(8) with the numbers inside the parenthesis(4x and 5).
32x+40=136
Subtract 40 from both sides
32x=96
Divide both sides by 32 so the only thing remaining on the side of the variable is only the variable itself.
Final Answer: x= 3
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3 years ago
A.X B.Y C.Z D.C really need help with this one not really sure about the answer
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Angle B corresponds to angle Y
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2 years ago
Read 2 more answers
What is the true solution to the equation below?
jarptica [38.1K]

Answer:

Step-by-step explanation:

some rules of logarithmic function

ln(a) - ln(b)=ln(\frac{a}{b})

e^{ln(a)}=a

ln(a)^{n}=nln(a) vice-versa nln(a)=ln(a)^{n}

If ㏑(a) = ㏑(b), then a = b

∴ 2ln(e^{ln(2x)})-ln(e^{ln(10x)})=ln(30)

Use the 2nd rule to simplify it

e^{ln(2x)}=2x\\e^{ln(10x)}=10x\\

2㏑(2x) - ㏑(10x) = ㏑(30)

Use the 3rd rule in the 1st term

∵ 2㏑(2x) = ㏑(2x)² = ㏑(4x²)

∴ ㏑(4x²) - ㏑(10x) = ㏑(30)

- Use the 1st rule with the left hand side

ln(4x^{2})-ln(10x)=ln(\frac{4x^{2}}{10x})\\\\ln(\frac{4x^{2}}{10x})=ln(30)\\\\ \frac{4x^{2}}{10x}=\frac{2x}{5}=\frac{2}{5}x\\\\ ln(\frac{2}{5}x)=ln(30)

Use the 4th rule

\frac{2}{5} x = 30

Multiply both sides by 5

∴ 2 x = 150

- Divide both sides by 2

∴ x = 75

The value of x = 75

3 0
3 years ago
Can anyone explain how to awnser -72/7 × -48/11?
kkurt [141]
Maybe search up Algebra calculator and type in the equation? idk
8 0
3 years ago
Let X be the random variable representing the number of calls received in an hour by a 911 emergency service. A portion of the p
ivolga24 [154]

For any distribution, the sum of the probabilities of all possible outcomes must be 1. In this case, we have to have

P(X=0)+P(X=1)+P(X=2)+P(X=3)+P(X=4)=1

We're told that p=P(X=1)=P(X=2), and we're given other probabilities, so we have

0.25+2p+0.10+0.05=1\implies2p=0.6\implies p=0.3

The expected number of calls would be

E[X]=\displaystyle\sum_xx\,P(X=x)

E[X]=0\,P(X=0)+1\,P(X=1)+\cdots+4\,P(X=4)

E[X]=1.4

6 0
2 years ago
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