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BlackZzzverrR [31]
3 years ago
12

Aman age is three times more than his sons age . Ten years ago he was five time his son age . What are present ages

Mathematics
2 answers:
hodyreva [135]3 years ago
5 0

Answer:

Son's age = 20 years

Father's age = 60 years

Step-by-step explanation:

Let son's age be x

Fathers age = 3x

Ten years ago:

Sons age = x - 10

Fathers age = 3x - 10

3x -10  = 5 * (x-10)

3x - 10 = 5x - 50

50 -10  = 5x - 3x

       40 = 2x

         x = 40/2

         x =20

Son's age = 20 years

Father's age = 60 years

viva [34]3 years ago
5 0

Answer:

Let the sons age be x years and aman's age be 3x years.

★ Ten years ago :

Sons age = x - 10 years

Aman's age = 3x - 10 years

<h3>⛈ <u>According to Question now,</u></h3>

→ 3x - 10 = 5(x - 10)

→ 3x - 10 = 5x - 50

Substracting 3x from both the sides we get :

→ -10 = 2x - 50

Substracting -10 from both sides we get :

→ 40 = 2x

Dividing both sides by 2 we get :

→ x = 20 years

<h3><u>Therefore,</u></h3>

  • Son's age = x = 20 years
  • Aman's age = 3x = 3(20) = 60 years
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3 0
3 years ago
Perform the following operations and write the answers in radical form.
strojnjashka [21]

Given:

Part A: \sqrt{7}+\sqrt{3}+\sqrt{98}-\sqrt{18}

Part B: 3 \sqrt{5}-3 \sqrt{11}+2 \sqrt{121}-3 \sqrt{90}

To find:

The simplified radical form.

Solution:

Part A: \sqrt{7}+\sqrt{3}+\sqrt{98}-\sqrt{18}

\sqrt{98}=\sqrt{7^2 \times 2} =7 \sqrt{2}

\sqrt{18}=\sqrt{3^2 \times 2} =3 \sqrt{2}

Substitute these in the given expression.

\sqrt{7}+\sqrt{3}+\sqrt{98}-\sqrt{18}=\sqrt{7}+\sqrt{3}+7\sqrt{ 2}-3\sqrt{ 2}

Add or subtract the coefficient of same radical.

                                    =\sqrt{7}+\sqrt{3}+(7-3)\sqrt{ 2}

                                    =\sqrt{7}+\sqrt{3}+4\sqrt{ 2}

Part B: 3 \sqrt{5}-3 \sqrt{11}+2 \sqrt{121}-3 \sqrt{90}

2 \sqrt{121}=2\sqrt{11^2}

           =2\times 11

           = 22

3 \sqrt{90}=3\sqrt{3^2 \times 10}

           =3\times 3 \sqrt{10}

           =9 \sqrt{10}

Substitute these in the given expression.

3 \sqrt{5}-3 \sqrt{11}+2 \sqrt{121}-3 \sqrt{90}=3 \sqrt{5}-3 \sqrt{11}+22-9 \sqrt{10}

8 0
3 years ago
P L E A S E H E L P
pychu [463]

Answer:

2100 square cm

Step-by-step explanation:

To find the AREA of a three-dimensional, non-circular figure, you would want to multiply length by width by height ( 20 x 7 x 15). Since we're just looking for area and not volume, this is the equation we'll be going with.

20 x 7 x 15 = 2100

Add in the units, and we get 2100 square cm.

Hope I could help.

3 0
4 years ago
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