Treat x^4 as the square of p: x^4 = p^2.
Then x^4 - 5x^2 - 36 = 0 becomes p^2 - 5p - 36 = 0.
This factors nicely, to (p-9)(p+4) = 0. Then p = 9 and p = -4.
Equating 9 and x^2, we find that x=3 or x=-3.
Equating -4 and x^2, we see that there's no real solution.
Show that both x=3 and x=-3 are real roots of x^4 - 5x^2 - 36 = 0.
Answer:
83%
Step-by-step explanation:
12 + 13 + 15 = 40
16 x 4 = 64
16 x 3 = 48
40/48 = 0.833333333333
Answer:
4
Step-by-step explanation:
the answer is 10.3, just search up how to solve percentage word problems
