Pllsssssssss hellllllppp

I can bake 3/4 of a cake in 5 minutes. How much of the cake canlbake in 1 minute?

lys-0071 [83]

Answer:

3/20 cake in 1 minute

Step-by-step explanation:

"3/4 of a cake in 5 minutes" is a verbal equation. We can divide both sides (that is, 3/4, 5 min) by 5 to determine the number of cakes I can bake in 1 minute:

3 5 min

-------- cake in -----------

4(5) 5

resulting in 3/20 cake in 1 minute.

3 0

2 years ago

Someone help please

Vlad1618 [11]

Answer:

32

Step-by-step explanation:

ok if it was a normal rectangle =

8 x 6

but the middle part takes 4 from the middle

since there are 2 rectangle

4/2 = 2

since there are lines

6 x 2 = 12 + another 12 since the rectangle on the bottom is the same as the top

24 + ...

6 - 4

2 x 4 = 8

24 + 8 =

32

3 0

3 years ago

Can someone help please

devlian [24]

the answer is x=47 hope this helps

3 0

3 years ago

Find the center of mass of the wire that lies along the curve r and has density =4(1 sin4tcos4t)

dolphi86 [110]

The mass of the wire is found to be 40π√2 units.

To calculate the mass of the wire which runs along the curve r ( t ) with the density function δ=5.

The general formula is,

Mass = $\int_a^b \delta\left|r^{\prime}(t)\right| d t$

To find, we must differentiate this same given curve r ( t ) with respect to t to estimate |r'(t)|.

The given integration limits in this case are a = 0, b = 2π.

Now, as per the question;

The equation of the curve is given as;

r(t) = (4cost)i + (4sint)j + 4tk

Now, differentiate this same given curve r ( t ) with respect to t.

$\begin{aligned}\left|r^{\prime}(t)\right| &=\sqrt{(-4 \sin t)^2+(4 \cos t)^2+4^2} \\&=\sqrt{16 \sin ^2 t+16 \cos ^2 t+16} \\&=\sqrt{16\left(\sin t^2+\cos ^2 t\right)+16}\end{aligned}$

Further simplifying;

$\begin{aligned}&=\sqrt{16(1)+16} \\&=\sqrt{16+16} \\&=\sqrt{32} \\\left|r^{\prime}(t)\right| &=4 \sqrt{2}\end{aligned}$

Now, use integration to find the mass of the wire;

$\begin{aligned}&=\int_a^b \delta\left|r^{\prime}(t)\right| d t \\&=\int_0^{2 \pi} 54 \sqrt{2} d t \\&=20 \sqrt{2} \int_0^{2 \pi} d t \\&=20 \sqrt{2}[t]_0^{2 \pi} \\&=20 \sqrt{2}[2 \pi-0] \\&=40 \pi \sqrt{2}\end{aligned}$

Therefore, the mass of the wire is estimated as 40π√2 units.

To know more about density function, here

brainly.com/question/27846146

#SPJ4

The complete question is-

Find the mass of the wire that lies along the curve r and has density δ.

r(t) = (4cost)i + (4sint)j + 4tk, 0≤t≤2π; δ=5

5 0

2 years ago

At the beginning of a population study, the population of a large city was 1.65 million people. Three years later, the populatio

Maksim231197 [3]

Answer:

C. 1.8027

Step-by-step explanation:

The exponential population growth model is given by:

$P(t) = P_{0}e^{rt}$

In which P(t) is the population after t years, $P_{0}$ is the initial population and r is the growth rate.

At the beginning of a population study, the population of a large city was 1.65 million people. Three years later, the population was 1.74 million people.

This means that $P_{0} = 1.65, P(3) = 1.74$