Answer:
39.6
Thirty nine point six
Step-by-step explanation:
9 x 4 2/5
9 x 22/5
198/5 = 39.6
Thirty nine point six
1.) The sum(addition) of 21 and 5 times(multiplication) a number f is(=) 61.
f = unknown number/variable [So 21 plus 5f(5 times f) equals 61]
21 + 5f = 61 [21(one-time) + 5f(number x variable) = 61(total)]
2.) Seventeen more(addition) than seven times(multiplication) a number j is(=) 87.
j = unknown number/variable [So 17 plus 7j(7 times j) equals 87]
17 + 7j = 87
3.) n = number of calls
18 + 0.05n = 50.50
[Company charges $18 plus five cents per call(n), and the total charge was $50.50]
4.) s = the number of students
40 + 30s = 220
[Tutor charges $40 plus $30 per student(s), and the total charge was $220]
Answer:
6:09
Step-by-step explanation:
clocks are cool and fun
if you look at delta y over x, you'll notice it always equals 2
i.e (22-2)/10-0 = 20/10 = 2
or (14-2)/6-0 = 12/6 = 2
or even (22-8)/10-3 = 14/7 = 2
This means that m (slope) is 2.
Now as for b. b is the y intercept and that value occurs when x = 0. On the table, when x = 0 y = 2 so b = 2.
y = mx + b becomes
y = 2x + 2
Answer:
Approximately 
(
.) (Assume that the choices of the 
passengers are independent. Also assume that the probability that a passenger chooses a particular floor is the same for all 
floors.)
Step-by-step explanation:
If there is no requirement that no two passengers exit at the same floor, each of these passenger could choose from any one of the floors. There would be a total of 
unique ways for these 
passengers to exit the elevator.
Assume that no two passengers are allowed to exit at the same floor.
The first passenger could choose from any of the floors.
However, the second passenger would not be able to choose the same floor as the first passenger. Thus, the second passenger would have to choose from only 
floors.
Likewise, the third passenger would have to choose from only 
floors.
Thus, under the requirement that no two passenger could exit at the same floor, there would be only 
unique ways for these two passengers to exit the elevator.
By the assumption that the choices of the passengers are independent and uniform across the floors. Each of these 
combinations would be equally likely.
Thus, the probability that the chosen combination satisfies the requirements (no two passengers exit at the same floor) would be:
.
