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3 years ago

What is the domain of the function

Mathematics

1 answer:

allochka39001 [22]3 years ago

7 0

Is the x under the square root too?

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96 is 32 percent of what number

deff fn [24]

32% of 300 is 96. 100% of 300 is 32 percent of 300 equals 96 so it is 300

8 0

3 years ago

A line goes through the points (1,8) and (9,12) what is the slope of the line? <br>Plz explain

Igoryamba

Answer:

2/3 or 0.67

Step-by-step explanation:

Slope = y2 - y1 /x2 - x1

Given

x1 = 1

y1 = 8

x2 = 9

y2 = 12

Slope = 12 - 8 /9 - 1

= 4/6

Reduce is by 2

2/3

0.67

8 0

3 years ago

29+d=54;24,25,26 what

kirza4 [7]

25 is the anwser you're looking for

8 0

3 years ago

Allen is trying to buy sneakers he has $50 to spend he finds a pair that he really likes that cost $58 if he has a 20% coupon ca

svetoff [14.1K]

First you would multiply 58 by .20 and you would receive 11.6
next you would subtract 11.y from 58 and get 46.4
so yes Allen can afford the sneakers

4 0

3 years ago

A dog breeder would like to know how many Dalmatian puppies are typically born in a litter. He conducts some research and select

podryga [215]

Answer:

c. 6.2 ± 2.626(0.21)

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 101 - 1 = 100

99% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 100 degrees of freedom(y-axis) and a confidence level of $1 - \frac{1 - 0.99}{2} = 0.995$ . So we have T = 2.626

The confidence interval is:

$\overline{x} \pm M$

In which $\overline{x}$ is the sample mean while M is the margin of error.

The distribution of the number of puppies born per litter was skewed left with a mean of 6.2 puppies born per litter.

This means that $\overline{x} = 6.2$

The margin of error is:

$M = T\frac{s}{\sqrt{n}} = 2.626\frac{2.1}{\sqrt{101}} = 2.626(0.21)$

In which s is the standard deviation of the sample and n is the size of the sample.

Thus, the confidence interval is:

$\overline{x} \pm M = 6.2 \pm 2.626(0.21)$

And the correct answer is given by option c.

5 0

3 years ago