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3 years ago

Can you solve this? :-)

Mathematics

1 answer:

Yuki888 [10]3 years ago

5 0

Option D might be correct

You might be interested in

45 units and is centered at

mariarad [96]

The correct question is:

A circle has a radius of 45 units and is centered at (-2.4, -4.8).

What is the equation of this circle?

Answer:

Equation of the circle is;

(x + 2.4)² + (y + 4.8)² = 2304

Step-by-step explanation:

The standard equation of a circle is;

(x - a)² + (y - b)² = r²

where;

(a,b) is the center of the circle and r is the radius of the circle

Now, from the question, the circle is centered at (-2.4, -4.8) and the radius is 45

Thus, plugging those values into the standard form of equation of a circle, we have;

(x - (-2.4))² + (y - (-4.8))² = 48²

This gives;

(x + 2.4)² + (y + 4.8)² = 2304

3 0

3 years ago

27/45=_/5?<br> 2/6=_/3?jjjjjj

VikaD [51]

Answer:

27/45 = 3/5

2/6 = 1/3

hope dis helps

4 0

4 years ago

Read 2 more answers

Does 15/25 x 25/15 = 0?

sergejj [24]

No, it does not equal 0. Lets multiply it out and see what it actually equals.
15/25 * 25/15
15*25 / 25*15
375 / 375
Anything over itself is 1, so the final answer for the multiplication is 1.

4 0

3 years ago

Select either relation (if the set is a relation but not a function), function (if the set is both a relation and a function), o

galina1969 [7]

Answer: The correct options are

(A) relation

(B) function.

Step-by-step explanation: We are given to check whether the following set is a relation or a relation and a function or neither :

A = {(1, 2) (2, 2) (3, 2) (4, 2)} .

Let us consider the following two sets :

U = {1, 2, 3, 4} and V = {2}.

Then, we see that the Cartesian Product of U and V is given by

U × V = {(1, 2) (2, 2) (3, 2) (4, 2)}.

Since a relation is a subset of Cartesian product, so the given set A is a relation.

Also, we know that a relation is a function if every first element is associated with one second element.

Since the relation A satisfies this condition, so the relation A is a function.

Thus, the given set A is both a relation and a function.

Option (A) and (B) are correct.

6 0

3 years ago

Are 2 + 6x and 2(3x + 1) equivalent

Solnce55 [7]

✳︎ ✳︎ ✳︎ ✳︎ ✳︎ ✳︎ Hello There! :)

To determine whether the two expressions are equivalent, we take the second expression and distribute 2:

2(3x+1)

6x+2=2+6x

And now we know the two expressions are equivalent. If you look, you will remember the Commutative Property that states:

a+b=b+a

In this case, a=6x and b=2.

So we know that the two expressions are equivalent.

Hope this helps! :)

$GraceRosalia$

$***************************************************\\Brainliest?$

3 0

3 years ago