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kvv77 [185]
3 years ago
10

When the product of 6 and the square of a number is increased by 5 times the number, the result is 4. Which equation represents

this situation? 6x2 + 5x - 4 = 0 6x2 + 5x + 4 = 0 62x + 5 + x = 4 6 + x2 + 5x = 4
Mathematics
2 answers:
adelina 88 [10]3 years ago
7 0

6{x}^{2} + 5x = 4
6 {x}^{2}  + 5x - 4 = 0
Eduardwww [97]3 years ago
5 0

Answer:

The equation that represents this situation is given by:

                           6x^2+5x-4=0

Step-by-step explanation:

Let " x " be any number.

Square of this number is: x²

and the product of 6 and square of a number is given by: 6x²

Now if this quantity is increased by 5 times the number; then the result is 4.

( 5 times the number x is given by: 5x )

This means that the expression could be given by:

                 6x^2+5x=4

On subtracting both side of the equality by 4 we obtain the equation as:

                      6x^2+5x-4=0

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Please write a equation for this table
Hitman42 [59]

Answer:

  y = 5x +2

Step-by-step explanation:

The point (0, 2) tells us the y-intercept is 2.

If we translate the table down 2 units by subtracting 2 from every y-value, it becomes ...

  6, 30

  -2, -10

  0, 0

  10, 50

We notice these values are all related by a factor of 5 (they are proportional). That means the equation will be a straight line with slope 5 and y-intercept 2.

  y = 5x +2

6 0
2 years ago
Kite WXYZ is graphed on a coordinate plane. What is the approximate perimeter of the kite? Round to the nearest tenth. 10.6 unit
Archy [21]

<u>Answer-</u>

<em>Perimeter of the kite is </em><em>16.2 units</em>

<u>Solution-</u>

As WXYZ is a kite, so two disjoint pairs of consecutive sides are congruent, i.e WX=XY and WZ=ZY

So, perimeter of the kite WXYZ is,

=2(\overline{WX}+\overline{WZ})

And

\overline{WX}=\sqrt{(1-3)^2+(1-4)^2}=\sqrt{(-2)^2+(-3)^2}=\sqrt{4+9}=\sqrt{13}

\overline{WZ}=\sqrt{(1-3)^2+(1+3)^2}=\sqrt{(-2)^2+(4)^2}=\sqrt{4+16}=\sqrt{20}

So, perimeter will be,

P=2(\sqrt{13}+\sqrt{20})=16.15\approx 16.2\ units

4 0
3 years ago
Read 2 more answers
Iv)<br>6x+3y=6xy<br>2x + 4y= 5xy​
Margaret [11]

Answer:

Ok, we have a system of equations:

6*x + 3*y = 6*x*y

2*x + 4*y = 5*x*y

First, we want to isolate one of the variables,

As we have almost the same expression (x*y) in the right side of both equations, we can see the quotient between the two equations:

(6*x + 3*y)/(2*x + 4*y) = 6/5

now we isolate one off the variables:

6*x + 3*y = (6/5)*(2*x + 4*y) =  (12/5)*x + (24/5)*y

x*(6 - 12/5) = y*(24/5  - 3)

x = y*(24/5 - 3)/(6 - 12/5) = 0.5*y

Now we can replace it in the first equation:

6*x + 3*y = 6*x*y

6*(0.5*y) + 3*y = 6*(0.5*y)*y

3*y + 3*y = 3*y^2

3*y^2 - 6*y = 0

Now we can find the solutions of that quadratic equation as:

y = \frac{6 +- \sqrt{(-6)^2 - 4*3*0} }{2*3} = \frac{6 +- 6}{6}

So we have two solutions

y = 0

y = 2.

Suppose that we select the solution y = 0

Then, using one of the equations we can find the value of x:

2*x + 4*0 = 5*x*0

2*x = 0

x = 0

(0, 0) is a solution

if we select the other solution, y = 2.

2*x + 4*2 = 5*x*2

2*x + 8 = 10*x

8 = (10 - 2)*x = 8x

x = 1.

(1, 2) is other solution

8 0
3 years ago
Justify each step in solving the equation -3(2x-3)=25-8x by writing a reason for each statement.
Mice21 [21]

Answer: x= 8.


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-6x +9 = 25-8x.

Step 2:  We need to get rid 9 from left side to get constant numbers on right side.

9 is being added on left side.

So, we would apply reverse operation of addition.

Therefore, applying Subtraction property of equality, we get

-6x +9-9 = 25-8x-9

-6x =16 -8x.

Step 3: We need to get rid 8x from right side.

The reverse operation of subtraction is addition.

Therefore, applying Addition property of equality, we get

-6x+8x =16 -8x+8x

2x = 16.

Step 4: We need to isolate it for x.

So, applying Division property of equality, we get

\frac{2x}{2}=\frac{16}{2}

<h3>x= 8.</h3>
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