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kvv77 [185]
3 years ago
10

When the product of 6 and the square of a number is increased by 5 times the number, the result is 4. Which equation represents

this situation? 6x2 + 5x - 4 = 0 6x2 + 5x + 4 = 0 62x + 5 + x = 4 6 + x2 + 5x = 4
Mathematics
2 answers:
adelina 88 [10]3 years ago
7 0

6{x}^{2} + 5x = 4
6 {x}^{2}  + 5x - 4 = 0
Eduardwww [97]3 years ago
5 0

Answer:

The equation that represents this situation is given by:

                           6x^2+5x-4=0

Step-by-step explanation:

Let " x " be any number.

Square of this number is: x²

and the product of 6 and square of a number is given by: 6x²

Now if this quantity is increased by 5 times the number; then the result is 4.

( 5 times the number x is given by: 5x )

This means that the expression could be given by:

                 6x^2+5x=4

On subtracting both side of the equality by 4 we obtain the equation as:

                      6x^2+5x-4=0

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Answer:

angle 2 is 85

Step-by-step explanation:

since its facing the 85

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Y_Kistochka [10]

The answer to 5x5 is 25

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3 years ago
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Drag each tile to the correct box.
Gwar [14]

Step-by-step explanation:

6x - 15 = 75, 6x = 90, x = 15.

2(2x - 1) = 46, 2x - 1 = 23, x = 12.

x + (x - 10) = 26, 2x = 36, x = 18.

5x - 3x = 10, 2x = 10, x = 5.

Hence the equations

in increasing order of x-values are:

5x - 3x = 10,

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3 0
3 years ago
HURRYYYYYYYYY!! What is the equation of the quadratic function with a vertex at (2, 25) and an x-intercept at (7,0)?
tangare [24]

Answer:

y=-(x-7)(x+3)

which is none of the choices provided.

Are you sure the question is right or even the choices?

You can even write it as:

y=-(x+3)(x-7) but this is still not a choice.

Step-by-step explanation:

The vertex form of a quadratic is y=a(x-h)^2+k.

This is called vertex form because it gives you the vertex is (h,k).

We are given that (h,k)=(2,25) which makes our equation:

y=a(x-2)^2+25.

We can find the value of a by plugging in the x-intercept (7,0) for (x,y) into:

y=a(x-2)^2+25

0=a(7-2)^2+25

0=a(5)^2+25

Subtract 25 on both sides:

-25=a(5)^2

-25=a(25)

Divide both sides by 25:

\frac{-25}{25}=a

-1=a.

So the equation for the quadratic is:

y=-1(x-2)^2+25

Let's put this into factored form since all the choices are in factored form.

This will require us to multiply the (x-2)(x-2) out:

y=-1(x-2)(x-2)+25

y=-1(x^2-2x-2x+4)+25

y=-1(x^2-4x+4)+25

y=-x^2+4x-4+25

y=-x^2+4x+21

Factor out -1:

y=-(x^2-4x-21)

WE need to find two numbers that multiply to be -21 and add to be -4:

y=-(x-7)(x+3)

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artcher [175]

Answer:

the average is 168

Step-by-step explanation:

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