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Sergeu [11.5K]
2 years ago
11

Write an equation of the line that passes

Mathematics
1 answer:
BaLLatris [955]2 years ago
7 0

Answer: y = 3x - 20

Step-by-step explanation: Start with the equation y=mx+b. Remember that the slope of the parallel line, m, will be the same. Now you have y = 3x + b. Next you have to find b, the y intercept. You can do so by using the point given, (6,-2).

-2 = (3) * (6) + b

b = -20

y=mx+b         y = 3x - 20

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If FG= 3 4 FG=34 miles and LM=1.5 LM=1.5 miles, then the scale factor for the dilation is _____.
Ugo [173]
The dilation is 35.5 miles
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3 years ago
Tay–Sachs Disease Tay–Sachs disease is a genetic disorder that is usually fatal in young children. If both parents are carri
BARSIC [14]

Answer:

a) 0.0156 = 1.56% probability that all children will develop the disease.

b) 0.4219 = 42.19% probability that only one child will develop the disease.

c) 0.1406 = 14.06% probability that the third children will develop the disease, given that the first two did not.

Step-by-step explanation:

For each children, there are only two possible outcomes. Either they carry the disease, or they do not. The probability of a children carrying the disease is independent of any other children, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

The probability that their offspring will develop the disease is approximately .25.

This means that p = 0.25

Three children:

This means that n = 3

Question a:

This is P(X = 3). So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 3) = C_{3,3}.(0.25)^{3}.(0.75)^{0} = 0.0156

0.0156 = 1.56% probability that all children will develop the disease.

Question b:

This is P(X = 1). So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 1) = C_{3,1}.(0.25)^{1}.(0.75)^{2} = 0.4219

0.4219 = 42.19% probability that only one child will develop the disease.

c. The third child will develop Tay–Sachs disease, given that the first two did not.

Third independent of the first two, so just multiply the probabilities.

First two do not develop, each with 0.75 probability.

Third develops, which 0.25 probability. So

p = 0.75*0.75*0.25 = 0.1406

0.1406 = 14.06% probability that the third children will develop the disease, given that the first two did not.

6 0
3 years ago
A package of 6 pairs of insulated gloves costs $31.74. What is the unit price of the pairs of gloves?
larisa86 [58]

Answer:

$5.29

Step-by-step explanation:

If a total of 6 gloves are $31.74, you  divide by the number of gloves (6) to get your answer

31.74/6= 5.29

5 0
2 years ago
Read 2 more answers
How do you solve this?<br><br> √63t^4
Mkey [24]
I hope this helps you




3.t^2.square root of 7
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3 years ago
Carson bought a coat for 40% of the original price, then another 15% off the discounted price. If the coat originally cost $149,
irinina [24]
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Steps: 149×0.6= 89.4
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Hope this helps ʕ•ᴥ•ʔ
5 0
3 years ago
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