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Nikolay [14]
2 years ago
6

Thomas rents a car for his vaccation the milliage included with the 54 miles forer every mile he drives over 54 miles he needs t

o pay 5 integer 4 by 5 dollar if he drives 69 miles how much extra does he needed to pay
Mathematics
1 answer:
Sauron [17]2 years ago
4 0

Answer:

$27

Step-by-step explanation:

Thomas rents a car for his vacation. The mileage include with the rental is 54 miles. For every mile he drives over 54 miles, he needs to pay $1 4/5. If he drives 69 miles, how much extra does he need to pay?

Total mileage included with the rental = 54 miles

Additional cost per mile after 54 miles = $1 4/5

Total miles Thomas drives = 69 miles

Extra miles Thomas drives = 69 miles - 54 miles

= 15 miles

how much extra does he need to pay?

Extra cost Thomas needs to pay = Additional cost per mile after 54 miles * Extra miles Thomas drives

= $1 4/5 * 15 miles

= 9/5 * 15

= (9 * 15) / 5

= 135/5

= 27

Extra cost Thomas needs to pay = $27

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6 0
2 years ago
(−4x <br> 4<br> +6x <br> 2<br> +3)−(5x <br> 2<br> −3)
LekaFEV [45]

Answer:

(-4x4+6x2+3)-(5x2-3)

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2x6          3

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_____       _____

-3x4       +  6

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3 0
3 years ago
Whose answer do you think is more likely to be representative of all the students in the schools? Explain.
maxonik [38]

Answer:

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Step-by-step explanation:

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4 0
2 years ago
Problem: a circle is inscribed in a square. The squares perimeter is 16 times the square root of 6. What is the probability of s
Oksi-84 [34.3K]
I got 21% at selecting a point outside.
Explanation: Since the perimeter is 16sqrt (6), each side must be 4sqrt (6)
This also means that the diameter is 4sqrt (6).

To find the area of a circle, we need to find the radius (2sqrt (6)).
Area of circle is pi × (2sqrt (6))^2 = 24pi or approximately 75.4 units^2
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Thus, let's take the area of the circle and subtract that from the area of our square to yield approx. 20.6 units^2
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8 0
3 years ago
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Firdavs [7]

Answer:

Choice A: (x,\frac{5}{2}x+ \frac{3}{2} ). for all real numbers.

Step-by-step explanation:

We are looking for points on the x-y plane which satisfy the equation y = 5/2x + 3/2, and these point are all those that lie on the graph of the equation, which are points (x,y) = (x,\frac{5}{2}x+ \frac{3}{2} ).

Looking at the other choices we see that choice B gives only 3 points, and regardless of whether they lie on the graph of y or not, this choice cannot be correct because 3 points are not all solutions.

The same goes for choice D.

And choice C is just the whole of x-y plane, therefore this cannot be the answer because not every point on the x-y plane is a solution to  y = 5/2x + 3/2

8 0
3 years ago
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