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3 years ago

Please help solve this

Mathematics

1 answer:

White raven [17]3 years ago

8 0

Answer:

BC~=AD (GIVEN )

CBA=CDA (altanate angles BC=AD)

C=A (altanate angles (BC=AD)

AAS

brainyliest please

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A garden is to be made in the form of an isosceles triangle. The equal side must be 4ft. Less than twice the base. The perimeter

Natali5045456 [20]

P = 77.
side (S1, S2) = 2(B) - 4.
P = S1 + S2 + B.
77 = (2B - 4) + (2B - 4) + B.
77 = 2B - 4 +2B - 4 + B.
77 = 5B - 8.
77 + 8 = 5B.
85 = 5B
B = 85/5
B=17 ft

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3 years ago

Write 4,670,000 in standard form

GrogVix [38]

Step-by-step explanation:

4,670,000

4.67x10^6

(im pretty sure this is correct) :)

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3 years ago

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13. Distributive Property<br> 3(x - 1) = 3x - ?

goblinko [34]

Answer:

$\huge\boxed{3x-3}$

Step-by-step explanation:

$3(x-1)=\\\\\text{Distribute: }\left \{ {{3*x=3x} \atop {3*-1=-3}} \right.\\\\3(x-1)=\boxed{3x-3}$

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3 years ago

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The area of the rectangle as a single expression

Ne4ueva [31]

Answer: $A=15x^2+6x-48$

Step-by-step explanation:

The area of a rectangle can be calculated with this formula:

$A=l*w$

Where "l" is the length and "w" is the width.

You can identify from the figure that the length and the width of this rectangle are:

$length=3(x+2)\\width=5x-8$

Then, you need to substitute this lenght and this width into $A=l*w$ :

$A=3(x+2)(5x-8)$

Now, apply Distributive property:

$A=(3x+6)(5x-8)\\\\A=15x^2-24x+30x-48$

Finally, you need to add the like terms. Then, you get:

$A=15x^2+6x-48$

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3 years ago

Solve by completing the square

Sveta_85 [38]

$\qquad\qquad\huge\underline{{\sf Answer}}☂$

Let's solve ~

$\qquad \sf \dashrightarrow \: {x}^{2} + 8x = 33$

$\qquad \sf \dashrightarrow \: {x}^{2} + 8x +16 = 33 + 16$

$\qquad \sf \dashrightarrow \: (x + 4) {}^{2} = 49$

$\qquad \sf \dashrightarrow \: x + 4 = \sqrt{49}$

$\qquad \sf \dashrightarrow \: x + 4 = \pm7$

Hence, there are two solutions ~

1. when x + 4 = 7

$\qquad \sf \dashrightarrow \: x + 4 = 7$

$\qquad \sf \dashrightarrow \: x = 7 - 4$

$\qquad \sf \dashrightarrow \: x = 3$

2. when x + 4 = -7

$\qquad \sf \dashrightarrow \: x + 4 = - 7$

$\qquad \sf \dashrightarrow \: x = - 7 - 4$

$\qquad \sf \dashrightarrow \: x = - 11$

I hope you understood ~

8 0

2 years ago