3 5/6 + (-1 1/6) Plz, help me with this. I will mark the brainliest.

The equation tan^2 x+1=sec^2 x is an identity true or false

Solnce55 [7]

Answer:

tan²x + 1 = sec²x is identity

Step-by-step explanation:

* Lets explain how to find this identity

∵ sin²x + cos²x = 1 ⇒ identity

- Divide both sides by cos²x

∵ sin x ÷ cos x = tan x

∴ sin²x ÷ cos²x = tan²x

- Lets find the second term

∵ cos²x ÷ cos²x = 1

- Remember that the inverse of cos x is sec x

∵ sec x = 1/cos x

∴ sec²x = 1/cos²x

- Lets write the equation

∴ tan²x + 1 = 1/cos²x

∵ 1/cos²x = sec²x

∴ than²x + 1 = sec²x

- So we use the first identity sin²x + cos²x = 1 to prove that

tan²x + 1 = sec²x

∴ tan²x + 1 = sec²x is identity

8 0

3 years ago

Calculate the number of subsets and the number of proper subsets for the set.

arlik [135]

A set of n elements has 2ⁿ subsets. One of these subsets is the set itself, so this set would have 2ⁿ - 1 proper subsets.

The given set has 4 elements, so it has 2⁴ = 16 subsets and 2⁴ - 1 = 15 proper subsets.

Just to illustrate the claim, we have

• subsets of size 0 (1 of these):

{ } (empty set)

• subsets of size 1 (4 of these):

{1/6}, {1/7}, {1/8}, {1/9}

• subsets of size 2 (6 of these):

{1/6, 1/7}, {1/6, 1/8}, {1/6, 1/9}, {1/7, 1/8}, {1/7, 1/9}, {1/8, 1/9}

• subsets of size 3 (4 of these):

{1/6, 1/7, 1/8}, {1/6, 1/7, 1/9}, {1/6, 1/8, 1/9}, {1/7, 1/8, 1/9}

• subsets of size 4 (1 of these):

{1/6, 1/7, 1/8, 1/9}

and the last one is the only subset that is not a proper subset, because that subset = the set.

6 0

2 years ago

7 times what equals 1?

Arturiano [62]

For this case, the first thing we must do is define a variable.
We have then:
x: unknown number
Doing the multiplication we have:
$(7) (x) = 1
$
From here, we clear the value of x.
We have then:
$x = \frac{1}{7} 
$
Therefore, we have:
$(7) ( \frac{1}{7} ) = 1
$
Answer:
7 times 1/7 equals 1

4 0

3 years ago

Read 2 more answers

Question 5^ Need help ... ASAP ... your help is really appreciated ...

goblinko [34]

Answer:

See below

Step-by-step explanation:

I think we had a question similar to this before. Again, let's figure out the vertical and horizontal distances figured out. The distance from C at x=8 to D at x=-5 is 13 units while the distance from C at y=-2 to D at y=9 is 11 units. (8+5=13 and 2+9=11, even though some numbers are negative, we're looking at their value in those calculations)

Next, we have to divide each distance by 4 so we can apply it to the ratio. 13/4= $\frac{13}{4}$ and 11/4= $\frac{11}{4}$ . Next, we need to read the question carefully. It's asking us to place the point in the ratio 3 to 1 from C to D. The point has to be closer to endpoint D because of this. Let's take each of our fractions, multiply them by 3, then add them towards the direction of endpoint D to get our answer (sorry if that sounds confusing):

$\frac{13}{4}*3 = \frac{39}{4}\\ 8-\frac{39}{4} = \frac{-7}{4}\\\frac{11}{4}*3 = \frac{33}{4} \\-2+\frac{33}{4} = \frac{25}{4}$

Therefore, our point that partitions CD into a 3:1 ratio is ( $\frac{-7}{4}, \frac{25}{4}$ ).

I'm not sure if there was more to #5 judging by how part B was cut off. From what I can understand of part B, however, I believe that Beatriz started from endpoint D and moved towards C, the wrong direction. She found the coordinates for a 1:3 ratio point.

Also, for #6, since a square is a 2-dimensional object, the answer needs to be written showing that. The answer for #6 is 9 units^2.

7 0

3 years ago

- Systems of Linear Equations & Inequalities

miv72 [106K]

Answer:

3.50

Step-by-step explanation:

3 0

2 years ago