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Rzqust [24]
3 years ago
5

PLEASE CLICK THE INAGE I NEED HELP PLEEEAAASSSE!!!​

Mathematics
2 answers:
morpeh [17]3 years ago
5 0

Answer:

Question 3: There are 12 boys in the class.

Question 4: 120 cookies were not oatmeal raisin.

Question 5: Target offers the best deal.

Step-by-step explanation:

If the ratio of girls to boys is 3:2, and there are 18 girls, that means there will be \frac{18}{3} * 2 = 6 * 2 = 12 boys.

Because there are 200 cookies total, and \frac{2}{5} of them are oatmeal raisin, that means that \frac{3}{5} of the cookies aren't oatmeal raisin. 200 * \frac{3}{5} = 40 * 3 = 120 cookies that aren't oatmeal raisin.

The cookies at Kroger have a unit rate of $0.45 per cookie, the cookies at Meijer have a unit rate of $0.50 per cookie, the cookies at Walmart have a unit rate of $0.38 per cookie, and the cookies at Target have a unit rate of $0.20 per cookie. So Target has the better buy.

ivann1987 [24]3 years ago
3 0
Step by step explanation
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Simplify the expression shown. (3m4n)2
laiz [17]

Answer:

9m⁸n²

Step-by-step explanation:

 (3m⁴n)²     Remove parentheses

= 3²m⁸n²     Square the 3

= 9m⁸n²

6 0
4 years ago
What will be the value of
madreJ [45]

The expression as given doesn't make much sense. I think you're trying to describe an infinitely nested radical. We can express this recursively by

\begin{cases}a_1=\sqrt{42}\\a_n=\sqrt{42+a_{n-1}}\end{cases}

Then you want to know the value of

\displaystyle\lim_{n\to\infty}a_n

if it exists.

To show the limit exists and that a_n converges to some limit, we can try showing that the sequence is bounded and monotonic.

Boundedness: It's true that a_1=\sqrt{42}\le\sqrt{49}=7. Suppose a_k\le 7. Then a_{k+1}=\sqrt{42+a_k}\le\sqrt{42+7}=7. So by induction, a_n is bounded above by 7 for all n.

Monontonicity: We have a_1=\sqrt{42} and a_2=\sqrt{42+\sqrt{42}}. It should be quite clear that a_2>a_1. Suppose a_k>a_{k-1}. Then a_{k+1}=\sqrt{42+a_k}>\sqrt{42+a_{k-1}}=a_k. So by induction, a_n is monotonically increasing.

Then because a_n is bounded above and strictly increasing, the limit exists. Call it L. Now,

\displaystyle\lim_{n\to\infty}a_n=\lim_{n\to\infty}a_{n-1}=L

\displaystyle\lim_{n\to\infty}a_n=\lim_{n\to\infty}\sqrt{42+a_{n-1}}=\sqrt{42+\lim_{n\to\infty}a_{n-1}}

\implies L=\sqrt{42+L}

Solve for L:

L^2=42+L\implies L^2-L-42=(L-7)(L+6)=0\implies L=7

We omit L=-6 because our analysis above showed that L must be positive.

So the value of the infinitely nested radical is 7.

4 0
3 years ago
The original cost of a pair of jeans was $50. The jeans are now on sale for $48. What is the percent of change of the cost of th
aleksandrvk [35]
4%

(50 x 4)/100 = $2.00

50 - 2.00 = $48.00
7 0
3 years ago
A Web site defines a regular polygon as “a polygon with all angles the same measure.” Is this definition valid?
grandymaker [24]

Answer:

Yes, because all regular polygons fit this definition.

Choice D is correct

Step-by-step explanation:

A polygon is said to be regular if it is equiangular that is all its angles are equal and equilateral which implies that all its sides have equal length. Examples of regular polygons include;

Regular pentagon

Regular octagon

3 0
3 years ago
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