Check the picture below.

$\bf 0=AB^2+6AB-121\implies \stackrel{\textit{using the quadratic formula}}{AB=\cfrac{-6 \pm \sqrt{6^2-4(1)(-121)}}{2(1)}}
\\\\\\
AB=\cfrac{-6 \pm \sqrt{520}}{2}\implies AB=\cfrac{-6 \pm \sqrt{4\cdot 130}}{2}
\\\\\\
AB=\cfrac{-6 \pm \sqrt{2^2\cdot 130}}{2}\implies AB=\cfrac{-6 \pm 2\sqrt{130}}{2}
\\\\\\
AB=-3\pm\sqrt{130}\implies AB=
\begin{cases}
\boxed{-3+\sqrt{130}}\\\\
-3-\sqrt{130}
\end{cases}$

since the distance AB cannot be a negative value, thus is not -3-√(130).

3 0

3 years ago

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An assembly line has two inspectors. The probability that the first inspector will miss a defective item is 0.06. If the defecti

Novay_Z [31]

Answer:

probability that both passes a defective item is 0.8742‬

<h3>Step-by-step explanation:</h3>

probability that the first inspector misses is Pr( 1st misses)= 0.06

therefore the probability he does not miss is

Pr(1st passes)= 1 - Pr( 1st misses) = 1 - 0.06 = 0.94

probability that the second misses is Pr( 2nd misses) = 0.07

therefore probability that 2nd does not miss is

Pr( 2nd passes) = 1- Pr( 2nd misses) = 0.93

probability that both passes a defective item is Pr(1st passes)*Pr( 2nd passes)

= 0.93*0.94 = 0.8742‬

7 0

3 years ago