Answer:
10
Step-by-step explanation:
Let's solve your equation step-by-step.
(−
1
/5
)(c)+2+c=
1
/5 (10c−20)
Step 1: Simplify both sides of the equation.
(−
1
/5
)(c)+2+c=
1
/5
(10c−20)
(−
1
/5
)(c)+2+c=(
1
/5
)(10c)+(
1
/5
)(−20) (Distribute)
−1
/5
c+2+c=2c+−4
(
−1
/5
c+c)+(2)=2c−4 (Combine Like Terms)
4
/5
c+2=2c−4
4
/5
c+2=2c−4
Step 2: Subtract 2c from both sides.
4/5
c+2−2c=2c−4−2c
−6
/5
c+2=−4
Step 3: Subtract 2 from both sides.
−6
/5
c+2−2=−4−2
−6
/5
c=−6
Step 4: Multiply both sides by 5/(-6).
(
5
/−6
)*(
−6
/5
c)=(
5
/−6
)*(−6)
c=5
Answer:
c=5
A is incorrect. The identity is for the Sin( A - B). It is not for the Cos(A - B)
B is closer, but NOT the answer. The sign in the middle is incorrect, for one thing. For another Cos(pi/2) = 0,, so the answer would be cos(theta) using this formula.
C The sign is correct in C. The problem is that it is the wrong formula for Cos(theta - pi/2). C should go
Cos(theta - pi/2) = cos(theta) cos(pi/2) + sin(theta)*sin(pi/2)
D. Looks like it's the correct answer. See the comment for C: The identity for C is actually correct for D.
Cos(theta)cos(pi/2) = 0 because cos(pi/2) =0
Sin(theta)*sin(pi/2) = Sin(theta) because Sin(pi/2) = 1
Answer D <<<<<< answer.
Answer:
Option C. continuous except x = 5 and x = 9.
Step-by-step explanation:
The given function is 
Now we have to check the continuity of the given function
We know if the denominator of a function which is in the form of a fraction is 0 then the given function is not continuous.
If we put x - 5 = 0
x = 5
and x - 9 = 0
x = 9
These are the two values of x for which the function is not defined.
Therefore option C. function is continuous except x = 5 and x = 9
is the correct answer.
Answer:
$1.89
Step-by-step explanation:
11.34/6= $1.89 for one bell pepper
