Does 4( − 11) = 15 − 4 have a solution , infinite or none?
1 answer:
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Answer:
Step-by-step explanation:
We have the angle in standard post has a sine ratio of
This means the opposite side length of the corresponding right triangle is 9 units and the hypotenuse is 41 units.
Using Pythagoras Theorem, the adjacent side length can be found using:
This implies that:
The cosine ratio is adjacent over hypotenuse.
Since we are in the second quadrant, the cosine ratio is negative;
Answer: The P-Value is .039337. The result is not significant at p < .01.
Step-by-step explanation:
In the following Chi square table attached, the value is of df=8 and chi square statistic value of 16.22 is found to be between (15.507, X²₀.₀₅) and ( 17.353, X²₀.₀₂₅).
Using the table for critical value calculation:-
Df=8 Critical value for 1%= 1.646, and we calculated our value of 17.353.
We can reject is on the basis of X²calculated > X²Critical.
The outcome doesn't falls to be in 1% of the distribution.
or
We can reject it on basis that the outcome between X²₀.₀₅ and X²₀.₀₂₅ whereas the required level of upper distribution is X²₀.₀₁
See the picture in the attached figure to better understand the problem
we know that
in the right triangle ABC
tan 80°=opposite side angle 80°/adjacent side angle 80°
tan 80°=BC/AC----->BC=AC*tan 80°-----> BC=75*tan 80°---> BC=425.35 m
the approximate height of the building=BC+<span>eye level
</span>the approximate height of the building=425.35+1.5----> 426.85 m
the answer is
the approximate height of the building is 426.85 m
we know that
in the right triangle ABC
tan 80°=opposite side angle 80°/adjacent side angle 80°
tan 80°=BC/AC----->BC=AC*tan 80°-----> BC=75*tan 80°---> BC=425.35 m
the approximate height of the building=BC+<span>eye level
</span>the approximate height of the building=425.35+1.5----> 426.85 m
the answer is
the approximate height of the building is 426.85 m