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kati45 [8]
3 years ago
5

Dylan has 128 prices of candy from Halloween . he eats half of his candy each week.

Mathematics
1 answer:
Scilla [17]3 years ago
5 0

Answer:

55.5 left over.

Step-by-step explanation:

128/2 = 64

half each week so;

1 whole = two weeks

8 weeks = 8

+ 1 = 8 1/2

so, 64/8.5

is going to be 55.5 left.

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A total of 160 children play in the city soccer league and 64 of the players are girls what percent of the players are girls
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40 percent of the children that play soccer are girls in the league

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3 years ago
A shop sells newspapers for a profit of 0.5%. His sales for the month of January were $8341.50. How much of this is profit?
Doss [256]
Amount of sales  of newspapers for the month of January = $8341.50
Percentage of profit for which the newspaper is sold = 0.5%
Then
Amount of profit made in the month of January = 0.5% * 8341.50 dollars
                                                                           = (0.5/100) * 8341.50 dollars
                                                                           = 4170.75/100 dollars
                                                                           = 41.707 dollars
                                                                           = 41.71 dollars
So the shop makes a profit of $41.71 in the month of January by selling newspapers worth $8341.50. I hope the procedure is perfectly clear for you to understand.
8 0
4 years ago
Use the four-step definition of the derivative to find f'(x) if f(x) = −4x^3 −1.
guapka [62]

\stackrel{de finition \textit{ of a derivative as a limit}}{\lim\limits_{h\to 0}~\cfrac{f(x+h)-f(x)}{h}} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{[-4(x+h)^3-1]~~ - ~~[-4x^3-1]}{h} \\\\\\ \cfrac{[-4(x^3+3x^2h+3xh^2+h^3)-1]~~ ~~+4x^3+1}{h} \\\\\\ \cfrac{[-4x^3-12x^2h-12xh^2-4h^3-1]~~ ~~+4x^3+1}{h} \\\\\\ \cfrac{-4x^3-12x^2h-12xh^2-4h^3-1+4x^3+1}{h}\implies \cfrac{-12x^2h-12xh^2-4h^3}{h}

\cfrac{h(-12x^2-12xh-4h^2)}{h}\implies -12x^2-12xh-4h^2 \\\\\\ \lim\limits_{h\to 0}~-12x^2-12xh-4h^2\implies \lim\limits_{h\to 0}~-12x^2-12x(0)-4(0)^2 \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \lim\limits_{h\to 0}~-12x^2~\hfill

7 0
2 years ago
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