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coldgirl [10]
3 years ago
8

Please help asap! (:

Mathematics
2 answers:
tiny-mole [99]3 years ago
8 0
Hello there! Let's calculate this. :)

<span><span><span><span><span><span>8<span>u^3</span></span>+<span>8<span>u^2</span></span></span>+6</span>+<span>4<span>u^3</span></span></span>−<span>6u</span></span>+3</span><span>

=<span><span><span><span><span><span><span>8<span>u^3</span></span>+<span>8<span>u^2</span></span></span>+6</span>+<span>4<span>u^3</span></span></span>+</span>−<span>6u</span></span>+3</span></span>

Combine Like Terms:<span>

=<span><span><span><span><span><span>8<span>u^3</span></span>+<span>8<span>u^2</span></span></span>+6</span>+<span>4<span>u^3</span></span></span>+<span>−<span>6u</span></span></span>+3</span></span><span>

=<span><span><span><span>(<span><span>8<span>u^3</span></span>+<span>4<span>u^3</span></span></span>)</span>+<span>(<span>8<span>u^2</span></span>)</span></span>+<span>(<span>−<span>6u</span></span>)</span></span>+<span>(<span>6+3</span>)</span></span></span><span>

=<span><span><span><span>12<span>u^3</span></span>+<span>8<span>u^2</span></span></span>+<span>−<span>6u</span></span></span>+9</span></span>

Answer:<span>

= D. <span><span><span><span>12<span>u^3</span></span>+<span>8<span>u^2</span></span></span>−<span>6u</span></span>+<span>9

Cheerio and have a lovely day! ^.^</span></span></span>
MAXImum [283]3 years ago
6 0
Hello!

You can only add variables with the same base and exponent

8u^3 + 4u^3 = 12u^3
8u^2 + 0 = 8u^2
0 + -6u = -6u
6 + 3 = 9

Put the sums together

12u^3 + 8u^2 - 6u + 9

The answer is D) 12u^3 + 8u^2 - 6u + 9

Hope this helps!

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The average Act score follows a normal distribution, with a mean of 21.1 and a standard deviation of 5.1. What is the probabilit
ohaa [14]

Answer:

0.43% probability that the mean IQ score of 50 randomly selected people will be more than 23

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question:

\mu = 21.1, \sigma = 5.1, n = 50, s = \frac{5.1}{\sqrt{50}} = 0.7212

What is the probability that the mean IQ score of 50 randomly selected people will be more than 23

This is 1 subtracted by the pvalue of Z when X = 23. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{23 - 21.1}{0.7212}

Z = 2.63

Z = 2.63 has a pvalue of 0.9957

1 - 0.9957 = 0.0043

0.43% probability that the mean IQ score of 50 randomly selected people will be more than 23

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Step-by-step explanation: hope this help

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34kurt
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sergij07 [2.7K]

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olganol [36]

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8.  combination; 15C5 = 3003

Step-by-step explanation:

7. The order of the committee member selections is not important. (It would be if specific people filled specific positions on the committee.) Hence, the number is a number of combinations of 25 people taken 6 at a time.

__

8. The order of players is not important, as it might be if specific choices filled specific positions on the team. (The problem statement gives no indication that is the case. It is only by our knowledge of basketball teams that we entertain the possibility that order might be important.) Hence, the number is a number of combinations of 15 people taken 5 at a time.

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Of course, nCk = n!/(k!(n-k)!)

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