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Tanzania [10]
2 years ago
11

The average person living in Argentinea consumes about 145 pounds of beef per year. The average person in the US consumes 3/5 as

much. How many pounds of beef does the average American consume every year?
Mathematics
1 answer:
Aleksandr [31]2 years ago
3 0
145*(3/5)=87
The Average Person In America Consumes 87 Pounds Of Beef Per Year.
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olganol [36]
The answer is 1/2. The reasoning is 1/2 x 1/2=1/4 1/4 x 1/2=1/8 fractions multiply on numerator and denominator then simplify
8 0
3 years ago
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PLEASE HELP ASAP!!!!!!
solmaris [256]

the answer would be x=6

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3 years ago
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Given a sample mean difference of 23, a standard error of 4.2, and a critical t value of 2.262, what are the values for the conf
erastova [34]

Answer: (13.4996, 32.5004)

Step-by-step explanation:

The confidence interval for mean difference is given by :-

(\overline{x}_1-\overline{x}_2)\pm t^*\times SE ,

where (\overline{x}_1-\overline{x}_2) = sample mean difference .

t^*= critical t value (two-tailed)

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Given : (\overline{x}_1-\overline{x}_2)=23

t^*=2.262

SE= 4.2

Now, the confidence interval for mean difference will be :-

23\pm (2.262)\times (4.2)\\\\= 23\pm9.5004\\\\=(23-9.5004,\ 23+9.5004)\\\\=(13.4996,\ 32.5004)

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8 0
2 years ago
(How to calculate (-2,8) and (1,6) that =-2/3
Pavel [41]
(6-8)/(1+2)= -2/3 the answer to the question
3 0
3 years ago
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DedPeter [7]

Answer:

False

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The line passes through (1, 5) with x- coordinate 1, thus

x = 1 ← equation of perpendicular line

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3 years ago
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