Answer:
q=12
Step-by-step explanation:
-11=61-6q
-11-61 =-6q
-72=-6q
q=72/6
q=12
This will be solved by solving for x first. Firstly you multiply the top equation by 2 and the bottom by -3. This will change both equation to (top)-10x+6y=-54 and (bottom) 27x-6y=-57. Now when you add the factors the y-values cancel out leaving you with; 17x=-3. now you have to divide by 17 on both sides giving you x=-0.17647058823 (not the prettiest solution but you can round if you want to). After that pick an equation to solve for y (I'm picking the top); the equation will be 5(-0.17647058823)+3y=-27. multiply the negative decimal and 5 to get -0.88235294117 (again not the prettiest). Add that to both sides which will give you 3y=-26.1176470588. After this divide both sides by 3 which will give you y=-8.70588235294. Your answer is (-0.17647058823,-8.70588235294) You can divide to the second or third decimal if needed-----remember that as you round from left to right on a decimal if it's below five you leave it and if it's above 5 then round up 1. I hope this help :)
The answer is b because you have 4 queens in a deck of cards and 13 clubs in a deck so if you add them you would get 17/52 cards
![\bf \sqrt{n}< \sqrt{2n+5}\implies \stackrel{\textit{squaring both sides}}{n< 2n+5}\implies 0\leqslant 2n - n + 5 \\\\\\ 0 < n+5\implies \boxed{-5 < n} \\\\\\ \stackrel{-5\leqslant n < 2}{\boxed{-5}\rule[0.35em]{10em}{0.25pt}0\rule[0.35em]{3em}{0.25pt}2}](https://tex.z-dn.net/?f=%5Cbf%20%5Csqrt%7Bn%7D%3C%20%5Csqrt%7B2n%2B5%7D%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Bsquaring%20both%20sides%7D%7D%7Bn%3C%202n%2B5%7D%5Cimplies%200%5Cleqslant%202n%20-%20n%20%2B%205%20%5C%5C%5C%5C%5C%5C%200%20%3C%20n%2B5%5Cimplies%20%5Cboxed%7B-5%20%3C%20n%7D%20%5C%5C%5C%5C%5C%5C%20%5Cstackrel%7B-5%5Cleqslant%20n%20%3C%202%7D%7B%5Cboxed%7B-5%7D%5Crule%5B0.35em%5D%7B10em%7D%7B0.25pt%7D0%5Crule%5B0.35em%5D%7B3em%7D%7B0.25pt%7D2%7D)
namely, -5, -4, -3, -2, -1, 0, 1. Excluding "2" because n < 2.
Answer:
b. {(-1.5, 9.5), (1,7)}
Step-by-step explanation:
brainliest please? :)
