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3 years ago

What the area of this shape

Mathematics

1 answer:

Rudiy273 years ago

3 0

Answer:it is 6,930

Step-by-step explanation:

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Urgent. There are 12 coloured counters in a bag. The counters are black, white or grey A counter is chosen at random. The probab

Nastasia [14]

Answer:

1/12

Step-by-step explanation:

Needed information

$\sf Probability\:of\:an\:event\:occurring = \dfrac{Number\:of\:ways\:it\:can\:occur}{Total\:number\:of\:possible\:outcomes}$

The sum of the probabilities of all outcomes must equal 1

Solution

We are told that the probability that the counter is not black is 3/4.

As the sum of the probabilities of all outcomes must equal 1, we can work out the probability that the counter is black by subtracting 3/4 from 1:

$\sf P(counter\:not\:black)=\dfrac34$

$\implies \sf P(counter\:black)=1-\dfrac34=\dfrac14$

We are told that the probability that the counter is not white is 2/3.

As the sum of the probabilities of all outcomes must equal 1, we can work out the probability that the counter is white by subtracting 2/3 from 1:

$\sf P(counter\:not\:white)=\dfrac23$

$\implies \sf P(counter\:white)=1-\dfrac23=\dfrac13$

We are told that there are black, white and grey counters in the bag. We also know that the sum of the probabilities of all outcomes must equal 1. Therefore, we can work out the probability the counter is grey by subtracting the probability the counter is black and the probability the counter is white from 1:

$\begin{aligned}\sf P(counter\:grey) & = \sf1-P(counter\:black)-P(counter\:white)\\\\ & =\sf 1-\dfrac14-\dfrac13\\\\ & = \sf \dfrac{12}{12}-\dfrac{3}{12}-\dfrac{4}{12}\\\\ & = \sf \dfrac{12-3-4}{12}\\\\ & = \sf \dfrac{5}{12}\end{aligned}$

7 0

2 years ago

Evaluate (4/25) 1/2 A 4/5 B 4/25 C2/5 D2/25

Phantasy [73]

(4/25) 1/2 = 4/50 = 2/25

D. 2/25

8 0

3 years ago

Read 2 more answers

Which of the following equations represents the linear relationship shown in the table below?

Sphinxa [80]

Answer:

Step-by-step explanation:

The equation is:

y = 2x + 3

Put x as 2.

y = 2(2) + 3

y = 4 + 3

y = 7

Put x as 3.

y = 2(3) + 3

y = 6 + 3

y = 9

Put x as 4.

y = 2(4) + 3

y = 8 + 3

y = 11

Put x as 5.

y = 2(5) + 3

y = 10 + 3

y = 13

6 0

3 years ago

A fair die with sides numbered 1, 2, 3, 4, 5, and 6 is to be rolled until a number greater than 4 first appears. what is the pro

AnnyKZ [126]

First two rolls have to be 1-4 that is 2/3 chance twice and the third can be 4or 5
2/3*2/3*1/3 + the chance that the fourth is the 5 or 6.
2/3*2/3*2/3*1/3

So the solution is : P=2/3*2/3*1/3 + 2/3*2/3*2/3*1/3

7 0

4 years ago

My last question someone help pls

lara [203]

Answer:

Step-by-step explanation:

7 0

3 years ago

What the area of this shape ​

What the area of this shape