Answer:
Step-by-step explanation:
x²-8x-20
=x²-10x+2x-20
=x(x-10)+2(x-10)
=(x-10)(x+2)
second factor is x+2
Answer:
$11.76
Step-by-step explanation:
We first need to find the amount of plywood for all birdhouses.
2 3/5 * 8 = 104/5 or 20.8 or 20 4/5
Now we can solve the cost for all the birdhouses by multiplying the total amount of plywood needed by the price per square foot.
20.8 * 0.56 = $11.648 or estimated $11.65
Remember, the question might be different, so don't submit anything yet. If the people who sell the plywood only sell in integer numbers (meaning you can't buy 4/5 of a square foot of wood but can only by amounts with no fractions), then Jenna must buy 21 square feet of plywood and will have a little bit of wood left over. Now solve just like before.
21 * 0.56 = $11.76
Therefore the answer is $11.76 if she can only buy an integer amount of plywood or estimated $11.65. I think the best answer is 11.76.
<span>If you had a check that you don't have sufficent funds for that has been run through the bank the bank will usually charge you an overdraft fee. This means that you have arranged an overdraft loan/agreement with the bank. The bank will go ahead and pay the fund to the person or company you wrote the check to. You will have a certain amount of time to put the money back into your account and pay the overdraft fee. Many banks will give you 24 hours to cover the check before they charge you a fee. The fee is usually around $25 dollars, but could be more depending on your bank rules. </span>
Answer:
y = 3sin2t/2 - 3cos2t/4t + C/t
Step-by-step explanation:
The differential equation y' + 1/t y = 3 cos(2t) is a first order differential equation in the form y'+p(t)y = q(t) with integrating factor I = e^∫p(t)dt
Comparing the standard form with the given differential equation.
p(t) = 1/t and q(t) = 3cos(2t)
I = e^∫1/tdt
I = e^ln(t)
I = t
The general solution for first a first order DE is expressed as;
y×I = ∫q(t)Idt + C where I is the integrating factor and C is the constant of integration.
yt = ∫t(3cos2t)dt
yt = 3∫t(cos2t)dt ...... 1
Integrating ∫t(cos2t)dt using integration by part.
Let u = t, dv = cos2tdt
du/dt = 1; du = dt
v = ∫(cos2t)dt
v = sin2t/2
∫t(cos2t)dt = t(sin2t/2) + ∫(sin2t)/2dt
= tsin2t/2 - cos2t/4 ..... 2
Substituting equation 2 into 1
yt = 3(tsin2t/2 - cos2t/4) + C
Divide through by t
y = 3sin2t/2 - 3cos2t/4t + C/t
Hence the general solution to the ODE is y = 3sin2t/2 - 3cos2t/4t + C/t
