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Serjik [45]
3 years ago
13

RATES AND RATIOS

Mathematics
1 answer:
docker41 [41]3 years ago
6 0
Blue to orange
6 : 5
24 : x

24 \div 6 = 4 \\ 5 \times 4 = 20

There are 20 orange M&M's.

Hope this helps. - M
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2 years ago
If x – 10 is a factor of x2 – 8x – 20, what is the other factor?
kkurt [141]

Answer:

Step-by-step explanation:

x²-8x-20

=x²-10x+2x-20

=x(x-10)+2(x-10)

=(x-10)(x+2)

second factor is x+2

5 0
3 years ago
Read 2 more answers
Jenna wants to build 8 birdhouses. She needs 2 3/5 square feet of plywood for each birdhouse. If the plywood costs $0.56 per squ
goldenfox [79]

Answer:

$11.76

Step-by-step explanation:

We first need to find the amount of plywood for all birdhouses.

2 3/5 * 8 = 104/5 or 20.8 or 20 4/5

Now we can solve the cost for all the birdhouses by multiplying the total amount of plywood needed by the price per square foot.

20.8 * 0.56 = $11.648 or estimated $11.65

Remember, the question might be different, so don't submit anything yet. If the people who sell the plywood only sell in integer numbers (meaning you can't buy 4/5 of a square foot of wood but can only by amounts with no fractions), then Jenna must buy 21 square feet of plywood and will have a little bit of wood left over. Now solve just like before.

21 * 0.56 = $11.76

Therefore the answer is $11.76 if she can only buy an integer amount of plywood or estimated $11.65. I think the best answer is 11.76.

3 0
2 years ago
3. Suppose your bank honors a check for which you don't have sufficient funds in your checking account. This action means that y
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6 0
3 years ago
Find the general solution of the following ODE: y' + 1/t y = 3 cos(2t), t &gt; 0.
Margarita [4]

Answer:

y = 3sin2t/2 - 3cos2t/4t + C/t

Step-by-step explanation:

The differential equation y' + 1/t y = 3 cos(2t) is a first order differential equation in the form y'+p(t)y = q(t) with integrating factor I = e^∫p(t)dt

Comparing the standard form with the given differential equation.

p(t) = 1/t and q(t) = 3cos(2t)

I = e^∫1/tdt

I = e^ln(t)

I = t

The general solution for first a first order DE is expressed as;

y×I = ∫q(t)Idt + C where I is the integrating factor and C is the constant of integration.

yt = ∫t(3cos2t)dt

yt = 3∫t(cos2t)dt ...... 1

Integrating ∫t(cos2t)dt using integration by part.

Let u = t, dv = cos2tdt

du/dt = 1; du = dt

v = ∫(cos2t)dt

v = sin2t/2

∫t(cos2t)dt = t(sin2t/2) + ∫(sin2t)/2dt

= tsin2t/2 - cos2t/4 ..... 2

Substituting equation 2 into 1

yt = 3(tsin2t/2 - cos2t/4) + C

Divide through by t

y = 3sin2t/2 - 3cos2t/4t + C/t

Hence the general solution to the ODE is y = 3sin2t/2 - 3cos2t/4t + C/t

3 0
3 years ago
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