Answer:
1. x² + 3x - 5 = 0
2. x² - x = 3 x + 7
4. 7x² + 14x = 0
Step-by-step explanation:
A Quadratic equation takes the form;
ax² + bx + c = 0
a, b, c are constants and a cannot be 0.
Options 1 fits this;
x² + 3x - 5 = 0
Option 2 fits this as well;
x² - x = 3 x + 7
x² -x - 3x - 7 = 0
x² - 4x - 7 = 0
Option 4 fits this as well if c = 0.
7x² + 14x + 0 = 0
To solve this, we are going to use the surface are of a sphere formula:

where

is the surface area of the sphere

is the radius of the sphere
We know for our problem that

and

, so lets replace those vales in our formula:



Now, we just need to solve our equation for

:





or

Since the radius of a sphere cannot be a negative number,

.
We can conclude that the radius of a sphere with surface area <span>2,122.64 </span>

is
13 in.
That equals <u>.0124031008</u>