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Answer:
Explanation:
From the given information:
Since the parent are normal; Let assume that their trait is Pp
The affected sister will be recessive in nature, so the trait will be pp
Now, the husband who is the groom will be a carrier with a probability of 2/3 since her sister is affected.
Also, the wife will be carrying a heterozygous trait since she is normal as well.
However, using Hardy-Weinberg assumption:
q = 0.02
Recall that:
Thus,
2pq = 0.0392
Finally, the required probability that there will be an affected offspring amongst the family is:
Answer:
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