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Genrish500 [490]
3 years ago
10

PLS HELP ASAP !!! WILL MARK BRAINLIEST !!

Mathematics
2 answers:
Olenka [21]3 years ago
4 0
I believe the answer is A
Over [174]3 years ago
3 0

Answer:

c is equal to e

Step-by-step explanation: a

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The current temperature of 14°F below zero is 26°F below the high temperature of the day. What is the high temperature for the d
faust18 [17]

Answer:

12* F

Step-by-step explanation:

-14* + 26* = 12

7 0
3 years ago
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Help please whats the answer
Ad libitum [116K]
<h3>Answer:</h3>

12 students

<h3>Explanation:</h3>

40% earned a B; 20% earned an A, so (40%+20% =) 60% got a "B or better."

60% of 20 students is ...

... 60/100 × 20 students = 1200/100 students = 12 students

5 0
3 years ago
What is the mean (average) and range (difference between highest &amp; lowest values) for the following list of numbers: 5, 3, 9
Mkey [24]

Answer:

Mean = 4 Range = 8

Step-by-step explanation:

Mean is just adding up all the numbers and dividing by the amount of numbers you used.

8 0
3 years ago
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164 less than the product of 82 and a number is 738.
Katen [24]
The unknown number would be 11

738 + 164 = 902
902 / 82 = 11
Ans: 11
5 0
3 years ago
Read 2 more answers
Each side of a square is increasing at a rate of 5 cm/s. At what rate (in cm2/s) is the area of the square increasing when the a
Naddika [18.5K]

The area of the square increasing at 30 \frac{cm^{2} }{sec}

The rate of change function is defined as the rate at which one quantity is changing with respect to another quantity. In simple terms, in the rate of change, the amount of change in one item is divided by the corresponding amount of change in another

Let the side of a square be x.

So,

Area of square = x^{2}

A =x^{2}

Differentiating with respect to time we get,

dA/dt = 2x dx/dt

When area = 9 cm^{2} the side becomes 3 cm

At x = 3cm and dx/dt = 5 cm/s (Given)

dA/dt = 2.3.5 = 30 \frac{cm^{2} }{sec}

Thus the area of the square increasing at 30 \frac{cm^{2} }{sec}

Learn more about rate of change here :

brainly.com/question/12786410

#SPJ4

4 0
2 years ago
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