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3 years ago

5x+2×+3-8+5x simplify

Mathematics

1 answer:

Tpy6a [65]3 years ago

6 0

Answer:

12x-5 (if 2x is 'x' and not a multiply sign)

Step-by-step explanation:

5x+2x+3-8+5x

=12x-5

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2 years ago

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tiny-mole [99]

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3 years ago

Suppose that a recent poll of American households about car ownership found that for households with a car, 39% owned a sedan, 3

RUDIKE [14]

Answer: Option 'a' is correct.

Step-by-step explanation:

Since we have given that

Probability of owned a sedan = 39%

Probability of owned a van = 33%

Probability of owned a sports car = 7%

n = 3

We need to find the probability that all three randomly selected households own a van.

So, Probability of getting all 3 own a van is given by

$(0.33)^3\\\\=0.035937\\\\\approx 0.036$

Hence, Option 'a' is correct.

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3 years ago

Subtract-3c2 + 12cd – 4d2 from 4c2 + 3cd + 2d?.

nirvana33 [79]

Answer:

Subtract $-3c^2 + 12cd - 4d^2$ from $4c^2 + 3cd + 2d^2$ we get $\mathbf{7c^2-9cd+6d^2}$

Step-by-step explanation:

We need to Subtract $-3c^2 + 12cd - 4d^2$ from $4c^2 + 3cd + 2d^2$

<em>(Note: Considering 2d^2 instead of 2d as thinking it typo error)</em>

Subtracting from means we have to subtract $4c^2 + 3cd + 2d^2 -(-3c^2 + 12cd - 4d^2)$

Subtracting:

$4c^2 + 3cd + 2d^2 -(-3c^2 + 12cd - 4d^2)\\=4c^2 + 3cd + 2d^2 +3c^2 - 12cd + 4d^2$

Combining like terms (Like terms are those that have same variables like 4c^2 and 3c^2 are like terms, 3cd and -12cd are like terms, 2d^2 and 4d^2 are like terms)

$=4c^2+3c^2 + 3cd-12cd + 2d^2+4d^2 \\=7c^2-9cd+6d^2$

So, Subtract $-3c^2 + 12cd - 4d^2$ from $4c^2 + 3cd + 2d^2$ we get $\mathbf{7c^2-9cd+6d^2}$

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3 years ago

A scientist measures the angle x and the distance y between the Earth and the Sun. Using complete sentences, explain how the sci

Nat2105 [25]

We know that :

$\spadesuit$ $Cos\theta = \frac{Adjacent Side}{Hypotenuse}$

Here Adjacent Side is BC, which is Distance between the Sun and Earth

Hypotenuse is CA, which is Distance between the Sun and Shooting star

⇒ $Cosx = \frac{BC}{CA}$

Given : Distance between Earth and Sun (BC) = y

⇒ $Cosx = \frac{y}{Distance\;between\;the\;Sun\;and\;Shooting\;Star}$

⇒ $Distance\;between\;the\;Sun\;and\;Shooting\;Star = \frac{y}{Cosx}$

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2 years ago

5x+2×+3-8+5x simplify​

5x+2×+3-8+5x simplify